Answer: -6=-4 or x=2,3
Step-by-step explanation:
Answer:
The area of rhombus PQRS is 120 m.
Step-by-step explanation:
Consider the rhombus PQRS.
All the sides of a rhombus are equal.
Hence, PQ = QR = RS = SP = 13 m
The diagonals PR and QS bisect each other.
Let the point at of intersection of the two diagonals be denoted by <em>X</em>.
Consider the triangle QXR.
QR = 13 m
XR = 12 m
The triangle QXR is a right angled triangle.
Using the Pythagorean theorem compute the length of QX as follows:
QR² = XR² + QX²
QX² = QR² - XR²
= 13² - 12²
= 25
QX = √25
= 5 m
The measure of the two diagonals are:
PR = 2 × XR = 2 × 12 = 24 m
QS = 2 × QX = 2 × 5 = 10 m
The area of a rhombus is:

Compute the area of rhombus PQRS as follows:


Thus, the area of rhombus PQRS is 120 m.
Answer:
you are multiplying baceicly
Step-by-step explanation:
3×2=6
Plug in the values.
3x^2-2y
3*3^2-2(5)
3*9-10
27-10
17
Next one.
2x^2-3y
2*3^2-3(5)
2*9-15
18-15
3
17-3= 15
The value of 3x^2-2y exceeds 2x^2-3y by 15.
I hope this helps!
~kaikers