Estimate the area of the figure below to the nearest hundredth.

0.25 with the 5 recurring as a fraction simplified

sweet [91]

Let x = 0.25555…
10x=2.555…
9x=2.3
90x=23
x=23/90

4 0

3 years ago

Edward went to the grocery store and bought some bro pounds of vegetables the vegetables cost 1.50 per pound. If he bought 3.25

Natali5045456 [20]

The cost of each vegetable is €1.50 per pound

Edward bought 3.25 pounds of carrot.

So the cost of 3.25 pounds of carrots = 3.25 × 1.50 = €4.875

He also purchased $1\frac{2}{10}= 1\frac{2}{5} =\frac{6}{5}$ pounds of beet.

Quantity of beet purchased = 6/5 = 1.2 pounds

So the cost of beet shall be = 1.50 × 1.2 = €1.80

He purchased 0.95 pounds of Broccoli

So the cost of Broccoli shall be = 0.95 × 1.50 = €1.425

Total amount spent = 4.875 + 1.80 + 1.425 = €8.10

Edward spent €8.10 on vegetables.

7 0

3 years ago

16. John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for t

nikklg [1K]

10*350= 3500
Total amount paid- 1500+3500= 5000
So an amount of $5000 was paid to cover the cost of $4500 within the 10 month period.

So you answer is A. 33%

3 0

3 years ago

Read 2 more answers

With respect to the diagram, which relationship is false if ∠FEA is supplementary to ∠HGD? m∠FEB + m∠HGD = 180° ∠HGD≅∠FEB m∠HGC

Minchanka [31]

6 0

3 years ago

Read 2 more answers

Suppose that the number of square feet per house are normally distributed with an unknown mean and standard deviation. A random

astraxan [27]

Answer:

1. The margin of error is of 66.96 square feet.

2. The 95% confidence interval estimate for the population mean using the Student's t-distribution is between 1433.04 square feet and 1566.96 square feet

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.08

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.08*\frac{151}{\sqrt{22}} = 66.96$

In which s is the standard deviation of the sample.

The margin of error is of 66.96 square feet.

The lower end of the interval is the sample mean subtracted by M. So it is 1500 - 66.96 = 1433.04 square feet

The upper end of the interval is the sample mean added to M. So it is 1500 + 314 = 1566.96 square feet

The 95% confidence interval estimate for the population mean using the Student's t-distribution is between 1433.04 square feet and 1566.96 square feet

6 0

4 years ago