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3 years ago

what is the equation in slope form of the line that is parallel to the given line and passes through the point (-3,1)

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

Answer:

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate the slope of the given line using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 2, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line

m = $\frac{2+4}{2+2}$ = $\frac{6}{4}$ = $\frac{3}{2}$

Parallel lines have equal slopes and using (a, b) = (- 3, 1), then

y - 1 = $\frac{3}{2}$ (x - (- 3)), that is

y - 1 = $\frac{3}{2}$ (x + 3) ← in point- slope form

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3 years ago

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3 years ago

In an all boys school, the heights of the student body are normally distributed with a mean of 71 inches and a standard deviatio

muminat

Answer:

15.87%

Step-by-step explanation:

First thing here is that we calculate the z-score which corresponds to 76

mathematically;

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plugging these values, we have;

z = (76-71)/5 = 5/5 = 1

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3 years ago

Solve 2x2 + 20x = −38. (1 point)

RoseWind [281]

Answer:

The solutions are $x=-5+\sqrt{6}$ and $x=-5-\sqrt{6}$

Step-by-step explanation:

we have

$2x^{2} +20x=-38$

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$x^{2} +10x=-19$ ------> $x^{2} +10x+19=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+19=0$

$a=1\\b=10\\c=19$

substitute

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}$

$x=\frac{-10(+/-)\sqrt{100-76}}{2}$

$x=\frac{-10(+/-)\sqrt{24}}{2}$

$x=\frac{-10(+/-)2\sqrt{6}}{2}$

$x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}$

$x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}$

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3 years ago

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what is the equation in slope form of the line that is parallel to the given line and passes through the point (-3,1)​

what is the equation in slope form of the line that is parallel to the given line and passes through the point (-3,1)