Which ones? Or all of them need to be answered ?
<em>ANSWER CORRECTLY ASAP </em>
<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)</em>
<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)</em>
<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)</em>
<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)4. A gas occupies a volume of 560 cm3 at a temperature of 120.0oC. To what temperature must the gas be lowered, if it is to occupy 400.0 cm3? Assume a constant pressure.</em>
<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)4. A gas occupies a volume of 560 cm3 at a temperature of 120.0oC. To what temperature must the gas be lowered, if it is to occupy 400.0 cm3? Assume a constant pressure.5. If 122 mL of oxygen are collected at 27.5oC and 740 mmHg, what will the volume be of the dry gas at STP? (760 mmHg = 101.3 kPa)</em>
<em>ANSWER CORRECTLY ASAP 1. An automobile tire has a pressure of 210.0 kPa at 20.0oC. What will be the tire pressure after diving, if the tire temperature rises to 35.0oC? (221 kPa)2. If a sample of gas has a volume of 355 mL at 44.1oC and 87.2 kPa, what will its volume be at STP? (263 mL)3. A tank of compressed gas has a maximum safe pressure limit of 826 kPa. The pressure gauge reads 388 kPa when the temperature is 24.1oC. What is the highest temperature the tank can withstand safely? (632 K)4. A gas occupies a volume of 560 cm3 at a temperature of 120.0oC. To what temperature must the gas be lowered, if it is to occupy 400.0 cm3? Assume a constant pressure.5. If 122 mL of oxygen are collected at 27.5oC and 740 mmHg, what will the volume be of the dry gas at STP? (760 mmHg = 101.3 kPa)6. A sample of neon gas has a volume of 0.261 L and a pressure of 108.5 kPa. What volume will the gas occupy at 96.5 kPa, if the temperature remains constant?</em>
Answer:
Step-by-step explanation:
Given
Required
Determine the equation
First, we calculate the intercepts using:
Where
b = Intercept on y axis.
a = Intercept on x axis.
From the question:
The equation becomes:
Multiply through by 3b
We have:
So:
Make b the subject
Substitute in to get the equation
Make 3y the subject
Make y the subject
Answer:
First Equation answer: r > 2
Second Equation answer: 7 (r+3)
Step-by-step explanation:
First Equation Explanation: Move variable to the left side (2r + 2r + 8 > 16)
See the like terms (4r > 16-8)
Divide both sides by inequality of 4 (4r > 8) 4r----> r > 2
Second Equation Explanation: Factor out 7.
