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Mama L [17]
3 years ago
8

Which is the most efficient way to italicize a row of text in every worksheet in a workbook?

Computers and Technology
1 answer:
oee [108]3 years ago
7 0
Control+A to highlight all text.
Then Control+i will italize the highlighted text.
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Which of the following will track every single connection outside the Web by IP address and URL? Clipper Chip National Security
astraxan [27]

The answer is proxy server

A proxy server acts as an immediate or a gateway between you, the proxy client (example, the browser) and the internet or the destination website that you want to visit. Proxy servers are designed to re-route traffic and obscure source and destination. For instance, if you want to request a page like brainly, a proxy server will be able to retrieve this page for you by providing only its IP address to the site and act as a mediator between clients and the requested server. This however, does not mean that there is no link between you and this website. It means that all the information along with the requests you made will be collected by the proxy server.

4 0
3 years ago
Read 2 more answers
Assume the variable myWord references a string. Write a statement that uses a slicing
givi [52]

Answer:

"myWord[-5:]"

Explanation:

So whenever you slice a string, the syntax in python is expressed as:

string[a:b:c]

where a=start index (this is included in the sliced string)

b = end index (this is excluded from the sliced string)

c = increment

If any of these are included, they are set to default values, where a=0, b=len(string), and c=1.

The increment isn't necessary here, and it's just so you know the syntax a bit more

Anyways, I'm assuming when the question asks to display "the last 5 characters in the string" it means in order? e.g "abcdefghijk" -> "ghijk" and not "abcdefghijk" -> "kjihg"

The last piece of information to know is what a negative index represents.

For example if I have the piece of code

"

string = "hello world"

print(string[-1])

"

This will output "d", and the negative 1 represents the last letter. If you did -2, it would output the 2nd to last letter and so on.

So to print the last 5 characters, we simply use the -5 as the starting index.  

"

string = "hello world"

print(string[-5:])

"

This will print "world" or in other words, the last 5 letters. The reason for this is because the -5 in the first spot means the starting index is the 5th to last letter, and when you have the : after the -5, this is the way of telling python you're slicing the string, and not indexing 1 character. You don't need to include another value after that, because it will default to the last index of the string, or more specifically the last index + 1, since the last index is still included.

So the last thing to know, is that if the string isn't greater than 5 characters, it just prints the entire string, and no errors are raised. You can test this out your self as well. So whenever you have a string that's less than 5 characters the entire string is outputted.

3 0
1 year ago
Why do people on Brainly verify answers that are wrong. I got 90% and 80% percent on my tests because of it
Bezzdna [24]
I feel that, you can’t trust it.
3 0
3 years ago
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Write a program to implement problem statement below; provide the menu for input N and number of experiment M to calculate avera
zalisa [80]

Answer:

Explanation:

#include<iostream>

#include<ctime>

#include<bits/stdc++.h>

using namespace std;

double calculate(double arr[], int l)

{

double avg=0.0;

int x;

for(x=0;x<l;x++)

{

avg+=arr[x];

}

avg/=l;

return avg;

}

int biggest(int arr[], int n)

{

int x,idx,big=-1;

for(x=0;x<n;x++)

{

if(arr[x]>big)

{

big=arr[x];

idx=x;

}

}

return idx;

}

int main()

{

vector<pair<int,double> >result;

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

int choice;

cin>>choice;

while(choice!=2)

{

int n,m;

cout<<"Enter N"<<endl;

cin>>n;

cout<<"Enter M"<<endl;

cin>>m;

int c=m;

double running_time[c];

while(c>0)

{

int arr[n];

int x;

for(x=0;x<n;x++)

{

arr[x] = rand();

}

clock_t start = clock();

int pos = biggest(arr,n);

clock_t t_end = clock();

c--;

running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;

}

double avg_running_time = calculate(running_time,m);

result.push_back(make_pair(n,avg_running_time));

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

cin>>choice;

}

for(int x=0;x<result.size();x++)

{

cout<<result[x].first<<" "<<result[x].second<<endl;

}

}

8 0
3 years ago
What is an effective way to record change management? (5 points)
yanalaym [24]

Answer:

Detailed Notes

Explanation:

I took the 2.04 quiz

3 0
3 years ago
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