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ahrayia [7]
3 years ago
9

a machine can reduce 21 inches of ribbon every 3 minutes. How many feet of ribbon can the machine make in one hour?

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0
Okay. Let's make a proportion for this. So we can do 21/3=x/60. Let's multiply cross way. So 21 x 60 is 1260. We multiply 3 by x to get 3x. So our equation will be 3x=1260. We can isolate the equation by 3, and 1260 divided by 3 is 420. So x=420. We then have to convert into feet. So 420 divided by 12 is 35. So it would be 35 feet. Therefore, the machine can make 35feet of ribbon in a hour.
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Is 29 prime or composite
Ksivusya [100]
29 is a composite number
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3 years ago
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I asked before and didn’t get an answer I really don’t understand this thanks.
dmitriy555 [2]
The answer is D, because that is what you should get when you multiply it out.

4x^2 times x^2 = 4x^4 because...

1) multiply the 4 and the one in front of the x on the second term = 4 then

2) multiply x^2 times x^2 to get x^4, not x^3, so you can immediately eliminate A and B to save time.

Now let's deal with the second part..."may or may not be" part

A polynomial is an expression with more than two algebraic terms

terms are like...
2x + 3y ---there's two terms there, eventhough the 2 and x are multiplied, it doesn't count (same with the 3 and y)
since it only have two terms, not more than two terms, it is called a binomial, not polynomial. I think that's what they mean by that

one term with a variable (y,x,and so on) is called a monomial

one term with no var is called a constant

there's many more but hope this gave you some help
3 0
3 years ago
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Product A requires 5 machine hours per unit to be produced, Product B requires only 3 machine hours per unit, and the company's
Lesechka [4]

Answer:

  Produce only Product B.

Step-by-step explanation:

The contribution margin per machine hour for product A is ...

  ($16 -$6)/(5 hour) = $2 per hour

The contribution margin per machine hour for product B is ...

  ($12 -$5)/(3 hour) ≈ $2.33 per hour

The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.

5 0
3 years ago
Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t
alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 + 6 = 12 seeds, which means that N = 12

6 treated, which means that k = 6

Five sprouted, which means that n = 5

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0
3 years ago
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natima [27]
Let the unknown no. be y
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3 years ago
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