a machine can reduce 21 inches of ribbon every 3 minutes. How many feet of ribbon can the machine make in one hour?

1 answer:

3 0

Okay. Let's make a proportion for this. So we can do 21/3=x/60. Let's multiply cross way. So 21 x 60 is 1260. We multiply 3 by x to get 3x. So our equation will be 3x=1260. We can isolate the equation by 3, and 1260 divided by 3 is 420. So x=420. We then have to convert into feet. So 420 divided by 12 is 35. So it would be 35 feet. Therefore, the machine can make 35feet of ribbon in a hour.

You might be interested in

7(h+3)=6(h-3) pls help

Nutka1998 [239]

Is this problem is about solving for h? If it is, here is the answer:

6 0

2 years ago

How do you solve (5^{2} - 1) ÷ 6

posledela

$( {5}^{2} - 1) \div 6 =$

$(25 - 1) \div 6 =$

$24 \div 6 = 4$

Note:

Do the square first, and then you do mathematic operation between the parentheses. And, then do the

mathematic operation in the outside of parentheses.

Thank you.

8 0

3 years ago

Read 2 more answers

Can someone pls answer all 6 questions pls? Pretty pls, except 1 and 5 thank you so much!!!

Maksim231197 [3]

2) C
3) B
4) C
6) I'm pretty sure its D but it could be C

7 0

2 years ago

Read 2 more answers

15x+27 how do you find the GCF

telo118 [61]

The correct answer would be 3 bc it goes into it 3 times!!:-D hope I helped u

8 0

3 years ago

Read 2 more answers

Help show work please

pantera1 [17]

We want to get rid of the stuff in the denomenator

gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x

muliplty the whole thing by 4x/4x

we get $\frac{x(x^2)}{4(2)+2(x+4)}=\frac{x^3}{2x+16}$

3 0

3 years ago