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mezya [45]
3 years ago
6

Product A requires 5 machine hours per unit to be produced, Product B requires only 3 machine hours per unit, and the company's

productive capacity is limited to 240,000 machine hours. Product A sells for $16 per unit and has variable costs of $6 per unit. Product B sells for $12 per unit and has variable costs of $5 per unit. Assuming the company can sell as many units of either product as it produces, the company should:
Produce only Product A.
Produce only Product B.
Produce equal amounts of A and B.
Produce A and B in the ratio of 62.5% A to 37.5% B.
Produce A and B in the ratio of 40% A and 60% B.
Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Answer:

  Produce only Product B.

Step-by-step explanation:

The contribution margin per machine hour for product A is ...

  ($16 -$6)/(5 hour) = $2 per hour

The contribution margin per machine hour for product B is ...

  ($12 -$5)/(3 hour) ≈ $2.33 per hour

The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.

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Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans
sammy [17]

Answer:

The average rate of change of the given function

A(x) =  1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function f(x) = x² - 2x -4

And given that x = a = -1 and  x=b = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

<u><em>Step(ii):-</em></u>

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1

<u><em>final answer:-</em></u>

The average rate of change of the given function

A(x) =  1

5 0
3 years ago
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At Stephanie's new job, she spent $6.50, $8, $7.25, $13.50, and $9.75 on lunch the first week. In the second week, Stephanie spe
MaRussiya [10]

Answer:

The mean for the second week is $2 less than the first and in percentage it is 22% less.

Step-by-step explanation:

The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:

sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75

sum1 = 45

Since she spent 10 less in the second week the sum is:

sum2 = sum1 - 10 = 45 - 10 = 35

The mean for each week is:

mean1 = sum1/5 = 45/5 = 9

mean2 = sum2/5 = 35/5 = 7

difference = mean1 - mean2 = 9-7 = 2

difference(%) = [2/9]*100 = 0.22*100 = 22%

The mean for the second week is $2 less than the first and in percentage it is 22% less.

6 0
3 years ago
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Fittoniya [83]
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Next, you can solve by substitution, so change x + y = 15 to y = 15 - x.

To find our x, substitute the y in 8x + 5y = 90 to get
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Now with our x, we can put 5 into the original equation x + y = 15 to get 5 + y = 15. Subtracting the 5, we get y = 10.

So, you have delivered 5 paper plate packages and 10 utensil packages.
8 0
3 years ago
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