<h3>
Answer: y = 12/(x^2)</h3>
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Explanation:
"y varies inversely as x^2" means y = k/(x^2) for some constant k.
Plug in (x,y) = (2,3) and solve for k
y = k/(x^2)
3 = k/(2^2)
3 = k/4
3*4 = k
12 = k
k = 12
The original equation updates to y = 12/(x^2)
As a check, plugging in x = 2 should lead to y = 3
y = 12/(x^2)
y = 12/(2^2)
y = 12/4
y = 3 ... we get the proper y value, so the answer is confirmed.
