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Thepotemich [5.8K]
3 years ago
12

If y varies inversely as x2 and y = 3 when x = 2, find the equation that connects x and y.

Mathematics
1 answer:
Bond [772]3 years ago
3 0
<h3>Answer:  y = 12/(x^2)</h3>

============================================================

Explanation:

"y varies inversely as x^2" means y = k/(x^2) for some constant k.

Plug in (x,y) = (2,3) and solve for k

y = k/(x^2)

3 = k/(2^2)

3 = k/4

3*4 = k

12 = k

k = 12

The original equation updates to y = 12/(x^2)

As a check, plugging in x = 2 should lead to y = 3

y = 12/(x^2)

y = 12/(2^2)

y = 12/4

y = 3 ... we get the proper y value, so the answer is confirmed.

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Answer:5r2+2

Step-by-step explanation:

Distribute the Negative Sign:

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=4r2+−3r+2+r2+3r

Combine Like Terms:

=4r2+−3r+2+r2+3r

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=5r2+2

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Step-by-step explanation:

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3 years ago
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jek_recluse [69]

Answer:

Equation: y = \frac{7}{4} x

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Step-by-step explanation:

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Plug in x which is 6 into the bolded equation.

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prime numbers
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AAAAAAA
2,3,5,7
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Answer:

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