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Basile [38]
3 years ago
14

The area of each triangular face of this right triangular prism is 8cm^2(squared).

Mathematics
1 answer:
otez555 [7]3 years ago
8 0
Nothing is shown.
The triangle is a right triangle, 9, 12 & 15.
The triangle's area = b*h/2 = 9*12/2 = 54 sq meters each end.

------------
The 3 rectangles are 10 by 9, 12 & 15
Area of the 3 = 10*(9 + 12 + 15) = 360 sq meters
-----
Total area = 360 + 2*54
= 468 sq meters

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Solve the following word problems using the BUCKS strategy. Remember to show your work.
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Answer:

5 is the answer of the question

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A briefcase has a three- digit lock code that doesn't include zero as a digit. What is the probability that the lock code consis
storchak [24]

Answer:

1/21.

Step-by-step explanation:

There are 9 digits and the total number of permutations of 3 from 9 is 9P3

= 9!/6!  = 504.

There are 4 even digits so the number of permutations of 3 from these 4 is 4!  (4-3)!  = 4*3*2 = 24.

So the required probability =  24/504

= 1/21.

5 0
3 years ago
The histogram presents the compressive strengths of a sample of concrete blocks hardened for 28 days.
dusya [7]

Answer:

The question is not complete but I have uploaded the image to complete the question.

The missing rectangle has a relative frequency of 0.15, and this is the same as the height.

Step-by-step explanation:

Let us define what a frequency and relative frequency are

The frequency of a datum is the number of times a given item (datum) appears in the data set.

While the relative frequency is the fraction or proportion of times taken from the whole in which an item/datum occurs.

So, from the image I uploaded, the relative frequency column represents the height of the histogram. Let the height of the missing rectangle be <em>x.</em>

Therefore the heights of the rectangles written from left to right are 0.05, 0.1, 0.15, <em>x, </em>0.25, 0.2, and 0.1.

From the definition of relative frequency, the total sum of relative frequency is 1, if represented as decimals or fractions it can either be expressed in percentage, or decimal (fractions). In this question, it is represented in decimal, and the sum of all the relative frequency is 1.

0.05 + 0.1 + 0.15 + <em>x </em>+ 0.25 + 0.2 + 0.1 = 1 ;

0.85+ <em>x </em>=1

Therefore, <em>x </em>= 1 - 0.85= 0.15

3 0
3 years ago
Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.
const2013 [10]

Answer:

a.

T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

b.

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

Step-by-step explanation:

Remember that for any curve      r(t)  

The tangent vector is given by

T(t) = \frac{r'(t) }{| r'(t)| }

And the normal vector is given by

N(t) = \frac{T'(t)}{|T'(t)|}

a.

For this case, using the chain rule

r'(t) = (  -10*2tsin(t^2) ,   102t cos(t^2)   )\\

And also remember that

|r'(t)| = \sqrt{(-10*2tsin(t^2))^2  +  ( 10*2t cos(t^2) )^2} \\\\       = \sqrt{400 t^2*(  sin(t^2)^2  +  cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t

Therefore

T(t) = r'(t) / |r'(t) | =  (  -10*2tsin(t^2) ,   10*2t cos(t^2)   )/ 20t\\\\ = (  -10*2tsin(t^2)/ 20t ,   10*2t cos(t^2) / 20t  )\\= ( -sin(t^2), cos(t^2) )

Similarly, using the quotient rule and the chain rule

T'(t) = ( -2t cos(t^2) , -2t sin(t^2))

And also

|T'(t)| = \sqrt{  ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t

Therefore

N(t) = T'(t) / |T'(t) |  =   (-cos(t^2) , -sin(t^2))

Notice that

1.   |N(t)| = |T(t) | = \sqrt{ cos(t^2)^2  + sin(t^2)^2 } = \sqrt{1} =  1

2.   N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0

b.

Simlarly

r'(t) = (2t,-6,0) \\

and

|r'(t)| = \sqrt{(2t)^2   + 6^2} = \sqrt{4t^2   + 36}

Therefore

T(t) =r'(t)/|r'(t)| =  (2t/ \sqrt{4t^2   + 36} , -6/\sqrt{4t^2   + 36},0)

Then

T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)

and also

|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 +   ( (3 t)/(9 + t^2)^{3/2})^2  +  0^2 }\\= 3/(t^2 + 9 )

And since

N(t) =T(t)/|T'(t)| =  (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)

6 0
3 years ago
Find the values of a through e that make these two relations inverses of each other.
SSSSS [86.1K]

A=-3.8

B=-2.6

C=1.7

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E=1.0

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3 years ago
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