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Alenkinab [10]
3 years ago
9

Who would have a difficult time responding to this survey question? Select all that apply.

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer:

18 and 65

Step-by-step explanation:

under 18 would be 17 and under, therefore not including 18 year olds. obviously they are not 19 yet either, so they wouldn't fall into either category, therefore they may be unsure of what to answer.

same with 65 year olds; they are more than 64 year old, but not yet /over/ 65, therefore they would not fit into either category either.

White raven [17]3 years ago
3 0
Honestly I’m not sure‍♀️ like it depends on what type of survey you’re trying to give. I’m 17, I don’t believe answering a survey would be so difficult to my age rank. Therefore, I believe 64 and 65.
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B. 29/40

40-18=22
22+36=58/80
58/2=29
80/2=40
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Solve for x <br>4^x/9^x=½<br>​
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Answer:

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Step-by-step explanation:

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3 years ago
What is the approximate area of a regular pentagon with a side length of 6 feet and a distance from the center to a vertex of 6
Sergio [31]
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Find the lateral surface area.
sveta [45]

Answer:

900 yd²

Step-by-step explanation:

You can draw the pattern that would need to be folded to make the figure, then find the area of that pattern (or "net"). It consists of a rectangle 10 yards wide and 60 yards long, together with another that is 20 yards long and 15 yards wide. The total area is the sum of these ...

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5 0
3 years ago
Suppose that we are testing a coin to see if it is fair, so our hypotheses are: H0: p = 0.5 vs Ha: p ≠ 0.5. In each of (a) and (
aleksley [76]

Answer:

H_0: p = 0.5\\H_a: p \neq 0.5

a. We get 56 heads out of 100 tosses.

We will use one sample proportion test  

x = 56

n = 100

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{56}{100}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}

                                       =1.2

refer the z table for p value

p value = 0.8849

a.  We get 560 heads out of 1000 tosses.

We will use one sample proportion test  

x = 560

n = 1000

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{560}{1000}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}

                                       =3.794

refer the z table for p value

p value = .000148

p value of part B is less than Part A because part B have 10 times the number the tosses.

6 0
2 years ago
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