Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then

when will it reach the ground level? let's set s(t) = 0

part B) check the picture below
Answer:
10x^2 y(2x + 3y)
Step-by-step explanation:
20x^3 y + 30x^2 y^2.
Factor 10x^2y out of 20x^3y.
10x^2 y (2x) + 30x^2 y^2
Factor 10x^2y out of 30x^2y^2.
10x^2 y (2x) + 10x^2 y (3y)
Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).
10x^2 y(2x + 3y)
you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option
The answer is b because 95 confidence is interval for the mean lifespan
Answer:
24
Step-by-step explanation:
The LCM or least common multiple of these numbers is 24
To get 24, you list all the multiple of these numbers until they all share at least one
So
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, <u>24</u>
6, 12, 18, <u>24</u>
8, 16, <u>24</u>
They all share 24 so this is the LCM
Hope this helps
-GoldenWolfX