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notka56 [123]
3 years ago
10

Timed, please hurry. thank you !

Mathematics
1 answer:
g100num [7]3 years ago
4 0
The answer to this question is 49
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I’ll give you brainiest if you answer correctly! I need help
Maurinko [17]

Answer:

y= -3/11x + 13

Step-by-step explanation:

hope this helps ( my cousins helped me) :))

7 0
3 years ago
Evaluate the expression for<br> x = 8, y = 4:<br> x + 10/y+5
Nesterboy [21]

Answer:

<h2><em>2</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>X=</em><em>8</em>

<em>y</em><em>=</em><em>4</em>

<em>Now</em><em>,</em>

<em>\frac{x + 10}{y + 5}  \\  =  \frac{8 + 10}{4 + 5}  \\  = \frac{18}{9}  \\  = 2</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

5 0
3 years ago
Read 2 more answers
Complete the division problem by determining the number that should be placed in the box.
jok3333 [9.3K]
Your answer would be 600 because 696-600=96
6 0
3 years ago
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Which of the following are solutions to the equation below? x2 + 6x + 9 =6
svetoff [14.1K]
The correct answer would be 3 +/- \sqrt{6}

In order to solve for this you must first get the equation equal to 0. 

x^2 + 6x + 9 - 6 ----> simplify like terms
x^2 + 6x + 3

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 1 (because it is the coefficient to x^2)
b = 6 (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}

\frac{-6 +/- \sqrt{6^{2} - 4(1)(3) } }{2(1)}

3 +/- \sqrt{6}

And those would be your two answers.
8 0
3 years ago
What is the simplified form of the quantity of x plus 7, all over the quantity of 6 − the quantity of x plus 5, all over the qua
vlabodo [156]

For this case we must simplify the following expression:

\frac {\frac {x + 7} {6- (x + 5)}} {x + 3}

We must apply double C:

\frac {(x + 7) (x + 3)} {6- (x + 5)} =

We apply distributive property in the numerator:

\frac {x ^ 2 + 3x + 7x + 21} {6- (x + 5)} =\\\frac {x ^ 2 + 10x + 21} {6- (x + 5)} =

In the denominator we have by law of signs:

- * + = -\\\frac {x ^ 2 + 10x + 21} {6-x-5} =

Different signs are subtracted and the sign of the major is placed:

\frac {x ^ 2 + 10x + 21} {- x + 1}

ANswer:

\frac {x ^ 2 + 10x + 21} {- x + 1}

5 0
3 years ago
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