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Afina-wow [57]
3 years ago
14

How do you workout this question?

Mathematics
2 answers:
pantera1 [17]3 years ago
7 0
1/2=0.5

1 divied by 2 = 0.5
1 divied by 2   0.5
 THEY ARE ALL 0.5 CAN I GET BRAINLIEST ANSWER 
also its better not 2 watch ur question B/C we think someone else is doing HW On it LOL !

vesna_86 [32]3 years ago
4 0
The answer to the whole process. is2
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2 show by calculation of nature of triangle AMK<br>3 CULCULATE BP MK AK
GarryVolchara [31]

Answer:

if he is the to form a 666

Step-by-step explanation:

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6 0
3 years ago
I need help with my math to day.‍♀️
ANTONII [103]

Answer:

8x + 1 + 6x + 5 = 90

14x +  6 = 90

14x = 84

x = 6

<DCB is 6x+5

6(6) + 5

36 + 5

41

8 0
3 years ago
Read 2 more answers
3.27x+1.28y+1.83x−2.77y
Firdavs [7]

Answer:

5.1x - 1.49y

Step-by-step explanation:

We need to add or substract like terms.

like terms are the terms that have the same variable, in this case:

3.27x and 1.83x are like terms, and adding them we get:

3.27x + 1.83x = 5.1x (you add only the coefficients and the x stays the same)

we do the same for the terms with 'y':

1.28y and −2.77y are like terms, but in this case we must substract because of the − sign:

1.28y −2.77y = -1.49y

the final answer is the conjunction of the two results that we obtained:

5.1x - 1.49y

8 0
3 years ago
What is the sum of the rational expressions below?<br> x/5+2/3x
Naya [18.7K]

Answer:

B

Step-by-step explanation:

x/5 + 2/3x

first you multiply both denominator.

this will be you denominator unless you can simplify it.

denominator=5 x 3X = 15X

now you times both denominator with the opposite numerator.

e.g. 5 x 2 and X x 3X.

=10 and 3X^2

now you and both numerators which is 3X^2 + 10

so the answer is b

7 0
3 years ago
Read 2 more answers
What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)
trasher [3.6K]

Answer:

<h2>7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x</h2>

Solution,

7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\  = 7 \sqrt[3]{2x}  - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x}  - 3 \times  \sqrt[3]{2 \times 2 \times 2x}  \\  = 7 \sqrt[3]{2x}  - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 3 \times 2 \times  \sqrt[3]{2x}  - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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