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4 years ago

15

draw a rectangle and another figure that is not a rectangle by tracing lines on a grid paper.describe how to find the perimeter

of both figures.

1 answer:

mihalych1998 [28]4 years ago

3 0

Draw a square to find the primeter count the squares along the outside object to find the primenter

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Xelga [282]

Your answer would be 0.03125

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4 years ago

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Can someone please tell me the answer

Alinara [238K]

• 12 - 9 = 3
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3 years ago

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Simply each expression by combining like<br> terms. -7W + 2W - 12W-W

tensa zangetsu [6.8K]

Answer:

answer is in the box. I hope that helps! :)

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3 years ago

Write as an expression and simplify

Alexus [3.1K]

Answer:

Part a) $(2m+7n)(2m-7n)$

Part b) $x^2-16xy+64y^2$

Part c) $216a^3b^6$

Part d) $(a^2-b^2)$

Step-by-step explanation:

Part a) The difference of the squares of 2m and 7n.

we know that

The difference of the squares formula is equal to

$(a^2-b^2)=(a+b)(a-b)$

substitute

$(2m)^2-(7n)^2=(2m+7n)(2m-7n)$

Part b) The square of the difference of x and 8y

The formula of the square of the difference between two numbers is equal to

$(a-b)^2=a^2-2ab+b^2$

substitute

$(x-8y)^2=x^2-2(x)(8y)+(8y)^2=x^2-16xy+64y^2$

Part c) The tripled product of 6a and b^2

we have

$(6ab^{2})(6ab^{2})(6ab^{2})=(6ab^{2})^3=(6^3)(a^3)(b^{2})^3=216a^3b^6$

Part d) The product of the sum of a and b and their difference

The expression is equal to

$(a+b)(a-b)$

The expression represent the difference of the squares between a and b

so

$(a+b)(a-b)=(a^2-b^2)$

7 0

3 years ago

Choose Yes or No to tell if the fraction 5/ 8 will make each equation true.

nirvana33 [79]

Yes
Yes
No
No hopefully I helped

6 0

3 years ago