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grandymaker [24]
3 years ago
14

If EF bisects CD, CG = 11x-5, GD=13x-15, and EF=12x+2, find EF.

Mathematics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

EF =  62

Step-by-step explanation:

Given

CG = 11x-5

GD=13x-15

EF=12x+2

Required

Determine EF

Since EF is a bisector of CD at G, then

CG = GD

11x- 5 = 13x - 15

Collect Like Terms

11x - 13x = 5 - 15

-2x = -10

Solve for x

x = -10/-2

x = 5

Substitute 5 for x in EF=12x+2

EF = 12 * 5 + 2

EF =  60+ 2

EF =  62

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Answer:

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Step-by-step explanation:

Let x represent the original voltage.

We have been given that the voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced 3 times.

The original voltage multiplied by itself for 3 times would be x\cdot x\cdot x=x^3.

Now, we will equate x^3 with 27/125 as:

x^3=\frac{27}{125}

We know that 27 is cube of 3 and 125 is cube of 5, so we can represent our equation as:

x^3=\frac{3^3}{5^3}

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Now, we will take cube root of both sides to find original voltage in the circuit as:

\sqrt[3]{x^3} =\sqrt[3]{(\frac{3}{5})^3}

Using property \sqrt[n]{a^n} =a, we will get:

x =\frac{3}{5}

Therefore, the original voltage in the circuit is \frac{3}{5} of a volt.

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In this problem, we consider that:

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<h3>What are the hypothesis tested?</h3>
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$H_{0}: p_{2}-p_{1}=0$

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The proportions and standard errors are given by:

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It is given by:

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Learn More about the z-distribution here: brainly.com/question/26454209

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