Vertical asymptotes happen at x=a if the function is undefined at x=a.
This is a rational functions, and rational functions are not defined when the denominator is zero, since you can't divide by zero.
In this case, the denominator is zero if
And thus the function has a vertical asymptote at x= -3/2
Answer:
See below ~
Step-by-step explanation:
Sides of a rhombus are equal.
⇒ QT = TS
⇒ x² - 4x - 10 = 6x + 14
⇒ x² - 10x - 24 = 0
⇒ x² + 2x - 12x - 24 = 0
⇒ x (x + 2) - 12 (x + 2) = 0
⇒ (x + 2)(x - 12) = 0
⇒ x = -2 or x = 12
Substitute both values and see which gives a positive value for QT :
<u>When x = -2</u> :
- QT = (-2)² - 4(-2) - 10
- QT = 4 + 8 - 10
- QT = 2
<u>When x = 12</u> :
- QT = (12)² - 4(12) - 10
- QT = 144 - 48 - 10
- QT = 86
The 2 possible answers are :
- x = -2, QT = 2
- x = 12, QT = 86
2. Terminating
3. Repeating
4. Like infactors
5. Unlike
6. Common denominator
Answer:
Divide x by 3
O using long polynomial division.
Step-by-step explanation:
