We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k
............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k
Since, this is absolute function
so, we can break it into two parts
we get
so,
...............Answer
If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5
No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000
No of ways 14 people can be arranged in 14 seats = 14!
Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
</span>
Answer:
y int = (0,5)
Step-by-step explanation:
hope this helps
