Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
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Since there is 101 Tickets,
Let S + A = 101
1.50S + 2.50A = $186.50
Adults + Students = 101
$186. 50 = $2.50 Adults + $1.50 Students
Answer is 35 Adults, and 66 Students.
Hope that helps!!!
Answer:
B. The ratio of the area of the scale drawing to the area of the painting is 1:16
C. The ratio of the perimeter of the scale drawing to the perimeter of the painting is 1:4
Step-by-step explanation:
The ratio of the area of similar figures/shapes = the square of the ratio of any of their side lengths
Since the scale drawing of the rectangular painting and the actual rectangular painting are similar, therefore,
The ratio of the area of the scale drawing to the painting = 1²:4²
= 1:16
Also, comparing the ratio of the perimeter of the scale drawing to the perimeter of the painting will be the same as the scale factor = 1:4
Answer:
the slope represents 10 dollars for every guest where x = guest
Step-by-step explanation:
