E^2x=(42-12)/3, that is easy
Then, the magic!
Ln(e^2x)=Ln[(42-12)/3]
2x.Ln(e)=Ln[(42-12)/3]. "Ln(e)=1"
X={Ln[(42-12)/3]}/2
Good luck!
M.
Answer:
The number must be a negative integer because -4+ any negative is a negative
Step-by-step explanation:
Setup Equation Based Off Merits
The second midpoint is (-15,8)
Answer:
2/3
Step-by-step explanation:
3 + 7 + 4 = 14
14 + 7 = 21
14/21 = 2/3