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koban [17]
3 years ago
9

What is the solution to the equation below?round your answer to two decimal places 3e^2x+ 12 =42

Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer:

c) x = 1.15

Step-by-step explanation:

3e^{2x}+12=42

Rearranging the equation

\\\Rightarrow 3e^{2x}=42-12\\\Rightarrow 3e^{2x}=30\\\Rightarrow e^{2x}=\frac{30}{3}\\\Rightarrow e^{2x}=10

Taking natural logarithm on both sides because lne^x=x

lne^{2x}=ln10\\\Rightarrow 2x=ln10\\\Rightarrow x=\frac{ln10}{2}\\\Rightarrow x=1.15129

∴ x = 1.15

VashaNatasha [74]3 years ago
5 0
E^2x=(42-12)/3, that is easy
Then, the magic!
Ln(e^2x)=Ln[(42-12)/3]
2x.Ln(e)=Ln[(42-12)/3]. "Ln(e)=1"
X={Ln[(42-12)/3]}/2
Good luck!
M.
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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The age of Sita = (x + 5) years.

And, the age of Gautam = x years.

Now,

5 years ago, the ratio of their ages was 3 : 2

\therefore \bf \frac{3}{2} \: = \frac{x \: + \: 5}{x}

Now by cross multiplying, we get,

3x = 2(x + 5)

3x = 2x + 10

3x - 2x = 10

<h3>x = 10 </h3>

Hence, the age of Sita = (x + 5) = (10 + 5) = 15 years.

And, the age of Gautam = x = 10 years.

Now,

The present age of Sita = 15 + 5 = 20 years. (Answer)

And, the present age of Gautam = 10 + 5 = 15 years. (Answer)

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Y_Kistochka [10]

Answer:

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Step-by-step explanation:

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x= 3.317 ×100/31

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4407= 39/100 × y

4407 =39y/100

4407×100=39y

4407 × 100/39=y

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Step-by-step explanation:

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Step-by-step explanation:

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6 0
3 years ago
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