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True [87]
3 years ago
5

The Museum of Science in Boston has an exhibit in which metal balls drop down a chute, bounce around, and wind up in one of 21 b

ins. After 1000 balls have dropped, the heights within the bins clearly follow a bell-shaped curve. The standard deviation is 3 bins.
About how many balls are in bins 1 through 17?

Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0
Refer to the diagram shown below.

Assume that approximately all the data is contained under the probability distribution curve within 3 standard deviations from the mean. It is actually 99.7%.
Therefore,
bin #1 corresponds to μ-3σ,
bin #11 corresponds to μ,
bin #21 corresponds to μ + 3σ.

Let x be the random variable for bin 17.
Then by interpolation,
\frac{x-\mu}{(\mu + 3\sigma )-\mu} = \frac{17-11}{21-11} \\\\ x-\mu = 1.8\sigma

The z-score for x is
z= \frac{x-\mu}{\sigma} = \frac{1.8\sigma}{\sigma} =1.8

The probability corresponding to bin #17 is (from standard tables)
P(z≤1.8) = 0.964
Therefore if there are 1000 balls, the sum of the balls in bins 1 to 17 is
0.964 * 1000 = 96.4 ≠ 96 balls.

Answer: 96 balls

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Clara has 8 coins worth 17¢. if the coins are all dimes and pennies, how many dimes and pennies does she have?
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Let x = the number of dimes
Let y =  the number of pennies.

There are 8 coins, therefore
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Subtract equation (1) from equation (2).
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4 years ago
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Comparing g(x) with f(x), you can see that the function f(x) is translated to the right by 6 units to produce g(x) which is equivalent to (x-6)²

<h3>Transformation of function</h3>

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Given the parent function f(x) = x² and the function g(x) = x²-12x +36

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Group the terms to have;

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Comparing g(x) with f(x), you can see that the function f(x) is translated to the right by 6 units to produce g(x) which is equivalent to (x-6)²

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2 years ago
According to the MIT Airline Data Project, American Airlines controlled 15.5% of the domestic market during a recent year. A ran
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Answer:

0.0143

Step-by-step explanation:

In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.

We proceed as follows;

The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155

Let’s call this probability p

The probability that he/she isn’t on the flight, let’s call this q

q =1 - p= 0.845

Sample size, n = 155

P(X < A) = P(Z < (A - mean)/standard deviation)

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= √ (125 x 0.155x 0.845)

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