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Paraphin [41]
3 years ago
15

Round to estimate 7.92+5.37

Mathematics
1 answer:
ehidna [41]3 years ago
5 0

Answer:13.3

Step-by-step explanation:When you add both numbers it equals to 13.29 which then adds up to 13.3 or 13.30 which is the same thing

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A number triple and tripped again is 729 what is the number show workings
kiruha [24]
Tripple then tripple means times 3 times 3
x times 3 times 3=x times 9
x time 9=729
divide both sides by 9
x=81

the numbe s 81
6 0
4 years ago
Read 2 more answers
Help for just 100 points!
34kurt
The answer is C

the mean is the average which is solved by adding up all of the numbers and then dividing that by how many numbers there are, 45/5 = 9
6 0
2 years ago
Read 2 more answers
If QR=x+29 and PS=x–16, what is the value of x?
Juli2301 [7.4K]

Answer:

  61

Step-by-step explanation:

PS is a midsegment of the triangle, so is half the length of the parallel base segment.

  2PS = QR

  2(x -16) = x +29 . . . . . substitute given expressions

  2x -32 = x +29 . . . . . eliminate parentheses

  x = 61 . . . . . . . . . . . . add 32-x

6 0
2 years ago
How many 2-digit numbers are multiples of 2 but not 3?
WARRIOR [948]

Answer:

30 numbers

Step-by-step explanation:

Two-digit numbers divisible by 2 are basically just the even two-digit numbers: 10, 12, 14,...96, 98.

Let's collectively divide all these numbers by 2:

10/2 , 12/2 , 14/2 , ... 96/2 , 98/2

5, 6, 7, ... 48, 49

Now subtract 4 from each of them:

5 - 4, 6 - 4, 7 - 4, ... , 48 - 4, 49 - 4

1, 2, 3, ... , 44, 45

So there are 45 multiples of 2 that are two-digit numbers.

The numbers that are both multiples of 2 and 3 are those that are multiples of 6:

12, 18, 24, ... , 96

We want to count how many there are, so divide all these numbers by 6:

12/6 , 18/6 , 24/6 , .... , 96/6

2, 3, 4, .... , 16

There are 15 numbers that are multiples of 2 and 3, so subtract 15 from 45: 45 - 15 = 30

The answer is 30.

Hope this helps!

7 0
4 years ago
Consider the system of equations.
Xelga [282]

Answer:

D and C

Step-by-step explanation:

Given the 2 equations

3x - y = 5 → (1)

2x + 3y = - 15 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate the y- term

9x - 3y = 15 → (3)

Add (2) and (3) term by term to eliminate y

11x + 0 = 0

11x = 0 ⇒ x = 0

Substitute x = 0 into either of the 2 equations and solve for y

Substituting into (2)

2(0) + 3y = - 15

0 + 3y = - 15

3y = - 15 ( divide both sides by 3 )

y = - 5

solution is (0, - 5 )

3 0
3 years ago
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