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seraphim [82]
2 years ago
9

18. In the diagram below, PQRS is a square Find the equation of the circle that will pass through the four vertices of the squar

e
R(2, - 2)

S

P(- 2, 2)

Q
Mathematics
1 answer:
mamaluj [8]2 years ago
6 0

An equation of the circle that will pass through the four (4) vertices of the square is (x + 2)² + y² = 2².

<h3>How to find the equation of this circle?</h3>

Mathematically, the general form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

Where:

  • h and k represents the coordinates at the center.
  • r is the radius of a circle.

<u>Note:</u> The center of a circle lies on the midpoint of the diagonal of a square, which is formed by joining its endpoints (opposite).

Midpoint on x-coordinate is given by:

Midpoint = (-2 - 2)/2

Midpoint = -4/2 = -2.

Midpoint on y-coordinate is given by:

Midpoint = (-2 + 2)/2

Midpoint = 0/2 = 0.

Thus, the center (h, k) = (-2, 0).

For the radius, we have:

r = √(-2)² + 0²

r = √4 = 2.

Substituting the parameters into the general equation, we have;

(x - (-2))² + (y - 0)² = 2²

(x + 2)² + y² = 2²

Read more on circle here: brainly.com/question/1615837

#SPJ1

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Mrs. Gomes found that 40% of students at her high school take chemistry. She randomly surveys 12 students. What is the probabili
zlopas [31]

Answer:

The correct answer to the following question will be "0.438".

Step-by-step explanation:

Just because Mrs. Gomes finds around 40% of students in herself high school are studying chemistry.  

Although each student becomes independent of one another, we may conclude:  

"x" number of the students taking chemistry seems to be binomial to p = constant probability = 0.40

Given:

Number of surveys

= 12

Exactly 4 students have taken chemistry:

=P(X\leq4)

=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)

=\Sigma_{0}^{4} C_{r}(0.4)^r(0.6)^{12-r}

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So that the above would be the appropriate answer.

5 0
3 years ago
How do you solve these?
Murrr4er [49]

Answer:

Step-by-step explanation:

The first and only rule really is to factor these down to their primes and then apply a very simple rule

For every prime, take out 1 prime for every prime under the root sign that equals the index. The rest are thrown away.

That's very wordy. Let's try and see what it means with an example

Take sqrt(27) The index is 1/2 (square root) That means we need two threes in order to apply the rule.

sqrt(27) = sqrt(3 * 3 * 3 ) For every two primes take out 1 and throw one away.

sqrt(27) = 3 sqrt(3) You can't take out that 3rd 3.

64 = 2 * 2 *2 *2 *2 * 2

4th root 64 =  <u>2*2*2 </u><u>*2</u><u> </u>* 2 *2

for every 4th root, you get to take 1 out and throw three away.

4th root 64 = 2 fourth root (2*2)

4th root 64 = 2 fourth root (4)

- 189 = -  <u>3 * 3 * </u><u>3</u> * 7

cuberoot (- 189) = For every 3 roots, you get to pull 1 out and throw the other two away.

3 cube (- 7) is your answer.

72 = 2 * 2 * 2 * 3 * 3

cube root (72) = 2 cube root(9) You don't have enough threes to do any more than what is done.

6 0
3 years ago
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