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Svetllana [295]
4 years ago
12

3. 8.2 m ? m Area = 41 m2

Mathematics
1 answer:
Nezavi [6.7K]4 years ago
8 0

Answer:

<h2>5 m</h2><h2 />

Step-by-step explanation:

area = L x W

41 = L ( 8.2)

L = 41 / 8.2

L = 5 m

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Standerd form example
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3951 is an example of a standard form. 

What standard form means is the number is written in numerical form. 

More examples: 5269, 95862, 125634, etc. 

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What is the length of ad
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It is 8 a.m. and the animals are waking up. In exactly 5 minutes. Sarah will chirp. Sarah will then chirp every 5 minutes until
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Once.

Step-by-step explanation:

To find when they chirp together, we must find the LCM of the two numbers. The LCM, or least common multiple of 13 and 5 is 65. Therefore, after 65 minutes is the first time they chirp together. Then we can multiply 65 by 2 to see if they chirp a second time. 65x2 is 130, but 8AM-10AM is only 120 minutes, therefore they do not chirp together more than 1 time.

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An English professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below the
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Solution :

The test is distributed normally with mean of 72.8 and the standard deviation of 7.3

Finding numerical limits for the D grade.

D grade : Scores below the top 80% and above the bottom 10%.

Let the bottom limit for D grade be $D_1$ and the top limit for D grade be $D_2$.

First find the bottom numerical limit for a D grade is :

$P(X

$P(X\leq D_1)= 0.10$

$P\left(\frac{X-\mu}{\sigma} \leq \frac{D_1-\mu}{\sigma}\right) = 0.10$

$P\left(Z \leq \frac{D_1-72.8}{7.3}\right) = 0.10$    ..........(1)

From (1)

$\frac{D_1 - 72.8}{7.3} = -1.28$

$D_1 = -1.28(7.3)+72.8$

      = 63.45

       ≈ 64

Now the top numerical limit for D grade :

$P(X>D_2)= 0.80$

$1-P(X\leq D_2)= 0.80$

$P(X\leq D_2)= 1-0.80$

$P(X\leq D_2)= 0.20$

$P\left(\frac{X-\mu}{\sigma} \leq \frac{D_2-\mu}{\sigma}\right) = 0.20$

$P\left(Z \leq \frac{D_2-72.8}{7.3}\right) = 0.20$    ..........(2)

From (2)

$\frac{D_2- 72.8}{7.3} = -0.84$

$D_12= -0.84(7.3)+72.8$

      = 66.668

       ≈ 67

Therefore, the numerical limit for a D grade is 64 to 67.

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WHAT IS 1/6 + 1/10 IN SIMPLEST FORM?
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Multiply denominator (in this case do 6x10)
Multiply the numerator (in this case do 1x1)
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