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Sophie [7]
3 years ago
11

On a coordinate grid, your campsite is located at ( -4, 10 ), and the next checkpoint is located at ( -10, -1 ). Each unit in th

e coordinate plane represents 1.55 miles. Find the distance you have to hike to reach the next checkpoint station. A) About 19.4 miles B) About 16.6 miles C) About 25.8 miles D) About 12.5 miles
Mathematics
2 answers:
marusya05 [52]3 years ago
4 0
Find the distance (in coordinate plane units) from (-4,10) to (-10,-1).

The change in x will be -6 and the change in y will be -11.

Thus, the distance between the 2 pts is, by the Pythagorean Theorem,

sqrt( [-6]^2 + [-11]^2 ) = sqrt(157).

Convert this to miles:

sqrt(157 units^2) = 12.6 units
 
                     1.55 mi
12.6 units * ------------- = 19.4 miles (answer)
                      1 unit
julsineya [31]3 years ago
4 0

Answer:

Distance = 19.4 miles

Step-by-step explanation:

On a coordinate grid, your campsite is located at ( -4, 10 ), and the next checkpoint is located at ( -10, -1 )

To find out the distance we apply distance formula

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

D=\sqrt{(-10+4)^2+(-1-10)^2}

D=\sqrt{(-6)^2+(-11)^2}

D=\sqrt{157}

D=12.53

Each unit in the coordinate plane represents 1.55 miles

Distance = 12.53 times 1.55 = 19.4 miles

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\displaystyle \large{\sum_{n=1}^{42}(6n-1)

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\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

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Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

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Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

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\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

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