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Naddik [55]
3 years ago
15

I will give brainliest to first (2x^2 − 7x^3 + 8x) + (−8x^3 − 3x^2 + 4)

Mathematics
2 answers:
valkas [14]3 years ago
5 0

Answer:

Step-by-step explanation:

-7x^3 - 8x^3 - 3x^2 + 2x^2 + 8x + 4

-15x^3 - x^2 + 8x + 4

cluponka [151]3 years ago
4 0

Answer:-15x^3-x^2+8x+4

Sry if I am wrong

Step-by-step explanation:

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Help please I need it as soon as possible ​
MAVERICK [17]

Answer:

y=1/2+3

Step-by-step explanation:

For the first one, 0 and 3. 0/2 is not possible so we just add 3.

Second, 1/2 is 0.5 of 1/2. Plus 3 is 3 1/2.

Third, 2/2 = 1 + 3 = 4.

And last, 3/2 = 1.5 or 1 1/2. 1 1/2 + 3 is 4 1/2

--

Hope this helps!

3 0
3 years ago
a car travels 30 1/5 miles in 2/3 of an hour. What is the average speed, in miles per hour, of the car?
Nadusha1986 [10]

Answer:

45.3 miles/hour

Step-by-step explanation:

30.2 / .666667

5 0
3 years ago
What is a rational number between -1 over 6 and -2 over 6?
belka [17]
A rational number for that question could be 5
7 0
3 years ago
What is the value of g(0)<br> -2<br> -1<br> 3<br> 6
Tanzania [10]

Answer:

Step-by-step explanation:

An x value of 0 can only be plugged into the equation that has a domain that includes 0. The first function's domain is between -2 and -4, so 0 is not included in that domain. In the third function, the domain is between 1 and 3, so 0 is not included in that domain, either. The middle function's domain does include 0 (0 falls between -2 and 1) so we can only evaluate this function at an x value of 0.

g(0) = -0 - 1 so

g(0) = -1

6 0
3 years ago
At t=0, a rock is dropped from rest from the top of a building 256 ft high. With what velocity will it strike the ground? What i
Rasek [7]

Answer:

128 ft / second.

Step-by-step explanation:

It's acceleration is due to gravity and is 32 ft s^-2.

To find the velocity when it hits the ground we use the equation of motion

v^2 = u^2 + 2gs    where  u = initial velocity, g = acceleration , s = distance.

v^2 = 0^2 + 2 * 32 * 256

v^2 = 16384

v =  128 ft s^-1.

4 0
3 years ago
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