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Ganezh [65]
3 years ago
8

What’s the 30th of the linear sequence -5,-2,1,4,7

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

The 30th term of the given sequence is 82.

<u>Step-by-step explanation</u>:

  • The general form of an Arithmetic Progression is a, a + d, a + 2d, a + 3d and so on.
  • The given linear sequence (-5,-2,1,4,7) is in the form of Arithmetic Progression with a common difference of 3.
  • -5, -5+3 = -2, -2+3 = 1, 1+3 = 4 and so on.

The nth term is given by the formula nth term = a + (n - 1) d

where  

a = first term

d = common difference

<u>To find the 30th term in the given sequence :</u>

The first term, a = -5 and the common difference, d = 3.

30th term = -5 + (30-1) 3

⇒ -5 + (29) 3

⇒ -5 + 87

⇒ 82

Therefore, the 30th term in the given sequence is 82.

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3 0
3 years ago
Can someone please help me with this!?
Katarina [22]

One way of solving this problem can be Heron's formula. It is a formula that allows us to compute the area of a triangle, knowing the length of its three sides.

For the sake of clarity, let's assume that the point in the top-left lies in the origin, and let's call it point A. Then, the "middle" point is point B, and the bottom-right point is point C.

If we fix the coordinate axis with the origin in A, we have the following coordinates for the three points:

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We can compute the length of any side using the formula for the distance between two points:

d(P,Q) = \sqrt{(P_x-Q_x)^2 + (P_y-Q_y)^2}

Plugging the approriate values, we get the following lenghts:

\overline{AB} = \sqrt{17},\quad \overline{BC} = 5,\quad \overline{AC} = \sqrt{74}

Now that we have the lengths, we can use Heron's formula: given the side lenghts a,b,\text{ and } c and the semiperimeter p, the area is given by

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If you plug our values, you will get an area of 6.5. So, unless I'm mistaken, none of the answers seem to mach, whereas 7 seems the best approximation.

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3 years ago
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