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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.
Answer:
687
Step-by-step explanation:
First, we want to find the area of the rectangle.
The formula is length times width, so it is 27*280, which equals 7560. We divide this by 11 to get 687.27272727.....(repeating)
The answer is 687.
Answer:
There is no slope, beacuse there is not a shown X
Step-by-step explanation:
The answer to the equation is 8
Answer:
4.99
Step-by-step explanation:
9.98 divide by 2