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Aneli [31]
3 years ago
6

1/2(x)=16 please explain the steps ty <3

Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

1/2(x)=16  x =32 and half of 32 is 16 so 1/2(x)=16

Step-by-step explanation:

what i did was first multiply 16 by 2 bc the answer would be half of what x was. i hope that helped!

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Which of the following equations is proportional? A. y=5x+6 B. y=8x+1 C. y=8x+0 D.y=5x+8
Dmitriy789 [7]

Answer:

pretty sure it is c but might wrong

Step-by-step explanation:

4 0
3 years ago
Find the distance between the ordered pairs. (6, 4) and (-3, 4)​
seropon [69]

Answer: = 9

There is really no steps for this answer...

4 0
2 years ago
Read 2 more answers
Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

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5 0
3 years ago
Read 2 more answers
Solve the inequality- x+18 ≥ 8x+4 or 15x-15 ≤ 15x+5<br><br> I give Brainliest!
r-ruslan [8.4K]

Answer:

x ≥ 2

0 ≤ 20 (not quite sure if the question is right)

Step-by-step explanation:

x+18 ≥ 8x+4

x - 8x ≥ 4 - 18

-7x ≥ -14

x ≥ \frac{-14}{-7}

x ≥ 2

________________

15x-15 ≤ 15x+5

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(I don't think this is the right question...cuz theres a 0)

6 0
2 years ago
Help!! Solving absolute value inequalities
goblinko [34]

Answer:

48. x \geq -7 or x \leq 31

51. x \leq 13 or x \geq 3

54. x < \frac{5}{2} or x > \frac{-15}{2}

57. x < \frac{18}{7} or x > -4

Step-by-step explanation:

48. | 12 - x | \leq 19

-There are two equations:

Equation 1:

12 - x \leq 19

      or

Equation 2:

12 - x \geq -19

Solving equation 1:

12 - x \leq 19

12- 12 - x \leq 19 - 12

-x \leq 7

\frac{-x}{-1} \leq \frac{7}{-1}

x \geq -7 (Inequality sign changed, because of dividing by a negative number)

-Solving equation 2:

12 - x \geq -19

12 - 12  - x \geq -19 - 12

-x \geq -31

\frac{-x}{-1} \geq \frac{-31}{-1}

x \leq 31 (Inequality sign changed, because of dividing by a negative number)

-Answers:

x \geq -7 or x \leq 31

51. | x - 8 | \leq 5

-There are two equations:

Equation 1:

x - 8 \leq 5

    or

Equation 2:

x - 8 \geq - 5

-Solving equation 1:

x - 8 \leq 5

x - 8 + 8 \leq 5 + 8

x \leq 13

-Solving equation 2:

x - 8 \geq - 5

x - 8 + 8 \geq - 5 + 8

x \geq 3

Answers:

x \leq 13 or x \geq 3

54. | 4x + 10 | < 20

-There are two equations:

Equation 1:

4x + 10 < 20

     or

Equation 2:

4x + 10 > -20

-Solving equation 1:

4x + 10 < 20

4x + 10 - 10 < 20 - 10

4x < 10

\frac{4x}{4} < \frac{10}{4}

x < \frac{5}{2}

-Solving equation 2:

4x + 10 > -20

4x + 10 - 10 > -20 - 10

4x > -30

\frac{4x}{4} > \frac{-30}{4}

x > \frac{-15}{2}

-Answers:

x < \frac{5}{2} or x > \frac{-15}{2}

57. | 7x + 5 | < 23

-There are two equations:

Equation 1:

7x + 5 < 23

     or

Equation 2:

7x + 5 > -23

-Solving equation 1:

7x + 5 < 23

7x + 5 - 5 < 23 - 5

7x < 18

\frac{7x}{7} < \frac{18}{7}

x < \frac{18}{7}

Solving equation 2:

7x + 5 > -23

7x + 5 - 5  > -23 - 5

7x > -28

\frac{7x}{7} > \frac{-28}{7}

x > -4

Answers:

x < \frac{18}{7} or x > -4

And we are finished.

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5 0
3 years ago
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