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Doss [256]
3 years ago
15

The diameter, D, of a sphere is 15 . Calculate the sphere's volume, V . Use the value 3.14 for pi , and round your answer to the

nearest tenth.
Mathematics
2 answers:
sergeinik [125]3 years ago
4 0

Answer:

V= 1767.2

Step-by-step explanation:

V=4/3πr3

(I'm pretty sure I rounded that right. If not it's 1767.15 before rounding. )

guapka [62]3 years ago
4 0

Answer:

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr³, were r is the radius.  

If we are told only that the diameter is 15, we must find the radius before applying the above formula.  The radius is r = 15/2.

The formula for the volume of a sphere is V = (4/3)πr³ yields

V = (4/3)(3.14)(15/2)^3, or

   =  1,766.3 cubic units

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Find the value of x when 6-4x = 6x-8x-2.
mestny [16]

Answer:

4

Step-by-step explanation:

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Step 3: Subtract 6 from both sides.

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here is a link:

https://www.mathpapa.com/algebra-calculator.html?q=6-4x%3D6x-8x-2.

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4 years ago
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Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

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79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

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79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

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{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
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