The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st
Step-by-step explanation:
Parallel lines have same slopes and different y-intercepts
To find which equation would graph a line parallel to 3y = x + 5
1. Put the equation in the form of y = mx + c
2. m is the slope of the line and c is the y-intercept
3. Look for the equation which has the same values of m and different
values of c
∵ 3y = x + 5
- Divide each term of the equation by 3 to put the equation in the
form of y = mx + c
∴ y =
x + 
∴ m = 
∴ c = 
The first answer:
∵ 3y = x + 1
- Divide each term of the equation by 3
∴ y =
x + 
∴ m = 
∴ c = 
∵ The two equations have same slope m = 
∵ The two equations have different y-intercepts c = 
and c = 
∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5
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Answer:
<em>The equation of the straight line in point - slope form</em>
<em>y +1 = -2 ( x-2)</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are C( 2,-1) and D(1,1)
Slope of the line

m = -2
<u>Step(ii):-</u>
Equation of the straight line passing through the point ( 2,-1) and having slope
m =-2
y - y₁ = m ( x- x₁)
y - (-1) = -2 ( x-2)
y +1 = -2 ( x-2)
<u><em>Final answer:-</em></u>
<em>The equation of the straight line</em>
<em>y +1 = -2 ( x-2)</em>
Answer: 9675
Step-by-step explanation: u don’t want to know do u
Answer:
1=5
2=1
3= 4
4=3
5=6
6=5
Step-by-step explanation: