The answer is (f o g)(x) = 2x^2 - 13
In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).
f(x) = 2x + 1 ----> Remove variable.
f(x) = 2( ) + 1 ----> Insert g(x)
(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute
(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify
(f o g)(x) = 2x^2 - 13
Answer:
$ 20
Step-by-step explanation:
Given that,
No. of notes Joe has = 4
The total value of the notes = $ 75
From the given notes, 4 notes that can make the sum of 75 would be
$ 50 note + $ 10 + $ 10 note + $ 5
= 50 * 1 + 10 * 1 + 10 * 1 + 5 * 1
= $ 75
Thus, the note that would not be included in the total value would $20 note as if we add it either the sum would be greater or lesser with four notes in combination.
The correct answer is x≈1.01
You're welcome. ;)
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions ()
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME= where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME= ≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5