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2 years ago

What is the perimeter of the rectangle? Area =33 sq m, width=3 , length=???

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

3 0

Answer:

the length = eleven meters.

Step-by-step explanation:

area divided by width.

33/3 = 11.

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The cube root of 5 times the square root of 5 over the cube root of 5 to the 5th power

Fiesta28 [93]

(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)

This becomes easier if we switch to fractional exponents:

5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)

Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.

1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)

That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:

1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5

7 0

3 years ago

Rohan makes $86,534.25 a year. How much will he pay in Social Security and Medicare taxes this year?

matrenka [14]

Answer:

porfavor en español pls para yo poder resolverlo

4 0

2 years ago

Read 2 more answers

How to find the area of a equilateral triangle that has a perimeter of 21?

Romashka-Z-Leto [24]

First, we have to find the length of each side of triangle. Equilateral triangle means 3 sides r in same length, so each side will be 21 ÷ 3 = 7
Now we need to calculate the height of the triangle. We can do this by Pythagoras theorem
Let the height be h
(7/2)^2 + x^2 = 7^2
The area should be 6.0621778265
Or u can say 6.06 corrected to 3 sig fig

8 0

3 years ago

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0

3 years ago

Noah spent 25 hours working on his car. He spent 4/5 of his time working on the transmission. How much time did Noah spend worki

xenn [34]

Answer:

5 hours

Step-by-step explanation:

4/5 is 20 of 25, so there are 5 hours left which is your answer!

6 0

3 years ago