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Lemur [1.5K]
3 years ago
9

Question 3 of 5

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer: B

Step-by-step explanation:

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Whats the answer to: 11x/18
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The value of that fraction depends on the value of 'x'.   Whatever 'x' happens
to be at the moment, the fraction is equal to about  61.1% of it.  And if 'x' ever
changes, then the value of the fraction also changes, immediately.
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Hi, you can get 15 points if you answer this...
RSB [31]

Answer:

Si

Step-by-step explanatio:

4 0
3 years ago
Read 2 more answers
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
3 years ago
Evaluate the perimeter of a rectangle.
likoan [24]
Answer= 22

Explanation
————————

2l+2w=p

2(8)+2(3)= 22
4 0
4 years ago
If the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center a
Sedbober [7]

The distance from the center to where the foci are located exists 8 units.

<h3>How to determine the distance from the center?</h3>

The formula associated with the focus of an ellipse exists given as;

c² = a² − b²

Where c exists the distance from the focus to the center.

a exists the distance from the center to a vertex,

the major axis exists 10 units.

b exists the distance from the center to a co-vertex, the minor axis exists 6 units

c² = a² − b²

c² = 10² - 6²

c² = 100 - 36

c² = 64

c = \sqrt{64}

c = 8

Therefore, the distance from the center to where the foci are located exists 8 units.

To learn more about the Pythagorean theorem here:

brainly.com/question/654982

#SPJ4

3 0
1 year ago
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