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3 years ago

Question 3 of 5

Mathematics

1 answer:

bagirrra123 [75]3 years ago

4 0

Answer: B

Step-by-step explanation:

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Prove algebraically that 0.5 recurring = 5/9

ad-work [718]

Answer and Step-by-step explanation:

We want to prove that 0.5555... = 5/9.

First, let's set 0.555... equal to x:

x = 0.555...

Now multiply this by 10:

10x = 5.555...

Now subtract the original from this new one:

10x = 5.555...

- x = 0.555...

______________

9x = 5

Note that we could cancel all the recurring terms because they were the same for both 5.555... and 0.555... since the 5's go up to infinity.

We now have 9x = 5, so divide both sides by 9:

x = 5/9, as desired

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3 years ago

Help a woman out here A

IgorLugansk [536]

Answer:

Step-by-step explanation:

4 0

3 years ago

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A railing needs to be build with 470.89 metric ton of iron the factory purchased only 0.38 part of required iron . How much iron

Marysya12 [62]

Answer:

291.9518 T are required for completion

Step-by-step explanation:

The remaining 0.62 part is ...

0.62 × 470.89 T = 291.9518 T

6 0

3 years ago

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What is the completely factored form of f(x)=x3−7x2+2x+4?

sladkih [1.3K]

Answer:

The Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

Step-by-step explanation:

Given;

$f(x)=x^{3} -7\times x^{2} +2x+4$

To solve for x we factorize the right side of

$f(x)=x^{3} -7\times x^{2} +2x+4$

Let Substitute x for various values to check whether remainder is zero.

$f(1)=1^{3} -7\times 1^{2} +2\times 1+4$

Hence $x-1$ is a factor of the function.

Do synthetic division to find the quotient

$1$ $1$ $-7$ $2$ $4$

$1$ $-6$ $-4$

_____________________

$1$ $-6$ $-4$ $0$

We get remainder 0 and quotient as,

$x^{2} -(6\times x)-4$

By using Quadratic Formula;

$x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

Plug 'a' , 'b' and 'c' value from $x^{2} -(6\times x)-4$ equation,

$x=\frac{-(-6)\pm\sqrt{-6^{2}-(4\times1\times -4 )} }{2\times1}$

$x=\frac{6\pm\sqrt{36+16 } }{2}$

$x=\frac{6\pm\sqrt{52} }{2}$

$x=3+\sqrt{13}$ and $x=3-\sqrt{13}$

The values of 'x' are $1$ , $3+\sqrt{13}$ and $3-\sqrt{13}$

So the Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

7 0

3 years ago

Using the graph below, what would the y-value (range) be for an x-value (domain) of -3?

Elza [17]

There is no graph havre me a nice day

8 0

3 years ago

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