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2 years ago

Please help & solve for x thank you!

Mathematics

1 answer:

vovikov84 [41]2 years ago

4 0

9514 1404 393

Answer:

x = 23.1

Step-by-step explanation:

The parallel lines make the left segments proportional to the right segments. This lets us write the equation ...

x/14 = 33/20

Multiplying by 14, we get ...

x = 14(33/20) = 7(33/10) = 23.1

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Add or subtract. use the least common multiple as the denominator what is 5/8-5/25

Vinvika [58]

Answer:

17/40

Step-by-step explanation:

First let's find the least common denominator. The denominators are 8 and 25 so we need to find the least common multiple of 8 and 25.

8=2*2*2

25=5*5

Since they share no common factors the least common multiple of 8 and 25 is 8*25 which is 200.

Now we convert the fractions:

5/8*25/25=125/200

5/25*8/8=40/200

Then we subtract:

125/200-40/200=85/200

Now we simplify it:

17/40

8 0

2 years ago

Read 2 more answers

Can the degree of a monomial ever be a negative? please explain why or why not.

lana [24]

Greetings!

Yes, the degree on a monomial can be negative:

Example:
$9x^{-2}$

This is equal to:
$1/9x^{2}$

Hope this helps.
-Benjamin

3 0

2 years ago

A $250 item is reduced to $205. Find the percent discount

SOVA2 [1]

Answer:

18%

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Marita orders 12 yards of material to make banners. If she needs 1 foot of fabric for each banner, how many banners can she make

Alik [6]

Well 3 feet=1 yard
so the conversion factor is 3ft/1yd

so 12 yards converted to feet is
12yd times 3ft/1yd
the yd will cancel and you will be left with 36 feet

each banner is 1 foot so 36/1=36
she can make 36 banners

7 0

2 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago