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vesna_86 [32]
3 years ago
10

suppose an investment of 1,800 doubles in value every 7 years. How much is the investment worth after 42 years?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0
$1,800*64


$115,200
 
That is how much the investment would be worth after 42 years.
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A woman invested 4 times as much as 5% as she did at 6%. The total amount of interest she earns is 1 year from both accounts is
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Answer:

at 5% interest, she invested $8,000

at 6% interest, she invested $2,000

Step-by-step explanation:

Let the invested amount at 5% interest = x

Let the invested amount at 6% interest = y

x = 4y - - - - (1) (A woman invested 4 times as much as 5% as she did at 6%)

5% of x = 0.05x

6% of y = 0.06y

0.05x + 0.06y = 520 - - - - (2) (The total amount of interest she earns is $520)

putting the value of x gotten in equation (1) into eqn (2):

0.05x + 0.06y = 520

where x = 4y

∴ 0.05(4y) + 0.06y = 520

0.2y + 0.06y = 520

0.26y = 520

y = 520 ÷ 0.26

y = $2000

from eqn (1)

x = 4y

since y = 2000

x = 4 × 2000

x = $8000

7 0
3 years ago
What is the volume of a rock if it has a density of 1.25g/ml if it has a mass of 7525g?
Rama09 [41]

Answer:

\boxed{\tt v= 6,020 \ mL}

Step-by-step explanation:

The density formula is

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Rearrange the formula for v. Multiply both sides of the formula by v, then divide both sides by d.

d*v=\frac{m}{v}*v

d*v=m

\frac{dv}{d}=\frac{m}{d}

v=\frac{m}{d}

The volume can be found by dividing the mass by the density. The mass is 7525 grams and the density is 1.25 grams per milliliter.

m= 7525 \ g\\d=1.25 \ g/mL

v=\frac{m}{d}

v=\frac{7525\ g}{1.25\ g/mL}

Divide. Note that the grams, or "g" will cancel each other out.

v=\frac{7525 \ }{1.25\ mL}

v=6020 \ mL

The volume of the rock is 6,020 milliliters.

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3 years ago
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Step-by-step explanation:

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