Ask question

Ask question

All categories

borishaifa [10]

4 years ago

15

The scale on a map indicates that 3 inches equal to 9 miles. If the distance on the map between a city library and a school is 1

5 inches, whats the actual distance between the two buildings?

1 answer:

Nitella [24]4 years ago

5 0

Answer: 45 miles.

Step-by-step explanation: 15 in/ 3in = 5 then take this 5 times the 9 miles = 45 miles.

You might be interested in

What is the value of x in the equation 5 x + 3 = 4 x ?

Y_Kistochka [10]

Answer:

x = -3

Step-by-step explanation:

5 x + 3 = 4 x

Solve for x

5x - 4x + 3 = 0

x + 3 = 0

x = -3

5 0

4 years ago

Read 2 more answers

Dexter deposited 6,300 into a saving account that earns 2.60% simple interest per year. How much interest will she earn in 4 yea

Gnoma [55]

Answer:

2

Step-by-step explanation:

6 0

3 years ago

A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time i

Likurg_2 [28]

R(t) = 4t
A(r) = π(r^2)

a) A(t) = A[r(t)] = π[r(t)]^2 = π[4t]^2 = 16π(t^2)

b) t = 4,

A(4) = 16*3.14*(16)^2 = 12,861.44

3 0

3 years ago

Please help this is due today please i really need help it’s due in 4 hours!!!

Anarel [89]

Answer:

y=36 and X=44

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)

trapecia [35]

$\huge \bf༆ Answer ༄$

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:13x + 5y = 670 \: \: \: \: \: (2)$

multiply the equation (2) with 2 [ it won't change the values ]

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y = 1340 \: \: \: \: \: (3)$

Now, deduct equation (1) from equation (3)

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y - 2x - 10y = 1340 - 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:24x = 1080$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 1080 \div 24$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 45$

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(2 \times 45) + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:90 + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 260 - 90$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 170$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 170 \div 10$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 17$

Hence, each van can carry (y) = 17 students in total.

5 0

3 years ago