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Readme [11.4K]
3 years ago
14

the average weight of the top 5 fish caught at a fishing tournament was 12.3 pounds. Some of the weights of the fish are shown i

n the table. What was the weight of the heaviest fish?
Mathematics
1 answer:
adoni [48]3 years ago
5 0
X+46.9=61.5 -46.9 -46.9 ------------------------ x=14.6
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Please help
Lapatulllka [165]
I think it’s A.6.3
Sorry if I’m wrong but I’m pretty sure it’s that.
7 0
4 years ago
In the triangles, Line segment A C is-congruent-to line segment F E and Line segment B C is-congruent-to line segment D E. Trian
choli [55]

Answer:

Line segment A B is longer than Line segment F D. This is the correct statement from the given statements.

Step-by-step explanation:

Given:

In ΔABC and ΔFDE

Segment AC≅Segment FE

Segment BC≅Segment DE

∠BCA = 72° and ∠DEF = 65°

Now by the property of a Triangle we know that

Side opposite to the greater angle is longer than the side opposite to the smaller angle.

So, Side opposite to the greater angle (∠BCA = 72°) is AB and

The side opposite to the smaller angle (∠DEF = 65°) is FD.

Therefore, side AB is Longer than side FD.  

4 0
3 years ago
Please help me with this
emmasim [6.3K]
The equation is put in slope intercept form which is y=mx+b

The slope is m and in this case it is -1/2.
To find the y intercept substitute in 0
for x then solve.
y =   - \frac{ 1}{2} (0) + 7
y = 7


5 0
3 years ago
Read 2 more answers
Will give brainliest, if its correct
Paul [167]

Answer:

C) -1

Step-by-step explanation:

(ax+3)²=36

<em>Square root both sides</em>

ax+3=6

<em>Subtract 3 from both sides</em>

ax=3

<em>Put x in</em>

-3a=3

a= -1

C) -1 would work.

6 0
4 years ago
Read 2 more answers
Find the indefinite integral using the substitution provided.
Nady [450]

Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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