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IgorC [24]
3 years ago
12

In the triangles, Line segment A C is-congruent-to line segment F E and Line segment B C is-congruent-to line segment D E. Trian

gles A B C and F D E are shown. The lengths of sides A C and F E are congruent. The lengths of sides B C and D E are congruent. Angle B C A is 72 degrees. Angle D E F is 65 degrees. Which statement correctly compares Line segment A B and Line segment F D? Line segment A B and Line segment F D are the same length. Line segment A B is longer than Line segment F D. Line segment A B is shorter than Line segment F D. Line segment A B is shorter than or the same length as Line segment F D.

Mathematics
1 answer:
choli [55]3 years ago
4 0

Answer:

Line segment A B is longer than Line segment F D. This is the correct statement from the given statements.

Step-by-step explanation:

Given:

In ΔABC and ΔFDE

Segment AC≅Segment FE

Segment BC≅Segment DE

∠BCA = 72° and ∠DEF = 65°

Now by the property of a Triangle we know that

Side opposite to the greater angle is longer than the side opposite to the smaller angle.

So, Side opposite to the greater angle (∠BCA = 72°) is AB and

The side opposite to the smaller angle (∠DEF = 65°) is FD.

Therefore, side AB is Longer than side FD.  

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3 years ago
On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

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