Find the center of the circle (x-2)^2+(y-8)^2=33
1 answer:
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Graph is attached below.
Step-by-step explanation:
We have to graph function y = 2x,
From equation, we can see a linear relationship between the values of x and y. This equation shows that the value of y is double than the value of x.
For example,
<u>x = 0</u>
y = 2(0)
y = 0
So, point would be (0,0)
<u>x = 1</u>
y = 2(1)
y = 2
So, point would be (1,2)
<u>x = 3</u>
y = 2(3)
y = 6
So, point would be (3,6)
<u>x = -1</u>
y = 2(-1)
y = -2
So, point would be (-1,-2)
<u>x = -3</u>
y = 2(-3)
y = -6
So, point would be (-3,-6)
By matching these points, a linear graph can easily be drawn. I have also attached the graph pic below.
Keywords: function, graph
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