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3 years ago

Find the center of the circle (x-2)^2+(y-8)^2=33

Mathematics

1 answer:

enyata [817]3 years ago

6 0

Answer:

The center is (2,8)

Step-by-step explanation:

The equation of a circle is written as

(x-h)^2+ (y-k)^2 = r^2

where ( h,k) is the center and r is the radius

(x-2)^2+(y-8)^2=33

The center is (2,8) and the radius is sqrt(33)

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2 years ago

(3*10)*8=240*(10*8) what is the property

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2 years ago

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

777dan777 [17]

Given:

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)$

$Midpoint=\left(\dfrac{-8}{2},\dfrac{2}{2}\right)$

$Midpoint=\left(-4,1\right)$

Slope of lines NY is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-3-5}{3-(-11)}$

$m=\dfrac{-8}{14}$

$m=\dfrac{-4}{7}$

Product of slopes of two perpendicular lines is -1. So,

$m_1\times \dfrac{-4}{7}=-1$

$m_1=\dfrac{7}{4}$

The perpendicular bisector of NY passes through (-4,1) with slope $\dfrac{7}{4}$ . So, the equation of perpendicular bisector of NY is

$y-y_1=m_1(x-x_1)$

$y-1=\dfrac{7}{4}(x-(-4))$

$y-1=\dfrac{7}{4}(x+4)$

$y-1=\dfrac{7}{4}x+7$

Add 1 on both sides.

$y=\dfrac{7}{4}x+8$

Therefore, the equation of perpendicular bisector of NY is $y=\dfrac{7}{4}x+8$ .

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2 years ago

The Millers receive a dinner bill for $122.75. The sales tax rate is 8%. They want to leave an 18% tip on the total bill after t

Aleks04 [339]

Answer:

they will start with $122.75 dollars to be paid and add on 8% of $122.75 which is $9.82.

the next step would be to add together 122.75+9.82 and you get $132.57

the last step woukd be to find what 18% of 132.57 is and that would be $23.86

add 132.57+23.86=$156.43

$156.43 is your answer

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2 years ago