Answer:
Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.
h(x) = f(x) + g(x)h(x)=f(x)+g(x) h(x) = f(x) - g(x)h(x)=f(x)−g(x)
h(x) = \frac{f(x)}{g(x)}h(x)=
g(x)
f(x)
h(x) = f(g(x))h(x)=f(g(x))
And many more.
The approach or formula to use depends on the question.
In this case, the combined function is:
f(x) = 75+ 10xf(x)=75+10x
The savings function is given as
s(x) = 85s(x)=85
The allowance function is given as:
a(x) = 10(x - 1)a(x)=10(x−1)
The new function that combined his savings and his allowances is calculated as:
f(x) = s(x) + a(x)f(x)=s(x)+a(x)
Substitute values for s(x) and a(x)
f(x) = 85 + 10(x - 1)f(x)=85+10(x−1)
Open bracket
f(x) = 85 + 10x - 10f(x)=85+10x−10
Collect like terms
mark as brainiest
f(x) = 85 - 10+ 10xf(x)=85−10+10x
f(x) = 75+ 10xf(x)=75+10x
Answer:
Step-by-step explanation:
Method 1: Taking the log of both sides...
So take the log of both sides...
5^(2x + 1) = 25
log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...
(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...
(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...
(2x)log 5 + log 5 - log 5 = log 25 - log 5
(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)
(2x)log 5 = log 5 <-- divide both sides by log 5
(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..
2x = 1
x=1/2
Method 2
5^(2x+1)=5^2
2x+1=2
2x=1
x=1/2
The picture won’t load re upload it so I can answer.
F(x) =x² - 10x, f⁻¹(x) =?
1st find the missing square of x²-10x, ==> (x-5)² - 25
y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5
Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}
Answer is:
x ≥ -18/5
2+4/9x ≥ 4+x
4/9x-x ≥4-2
4/9x-9/9x ≥2
- 5/9x ≥2 multiple by 9
-5x ≥2•9
-5x ≥18
x ≥ -5/18
