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2 years ago

Help me i need it

Mathematics

1 answer:

Fofino [41]2 years ago

7 0

Answer:

there too much lol I have no clue

Step-by-step explanation:

hop I help not really but yeah

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How do I find the answer to 4+3j=43

melamori03 [73]

4+3j=43
-4 from both sides
3j=39
then divide both sides by 3 to isolate j
j=12

8 0

3 years ago

Write the improper fraction as a mixed number in simplest form. 11/2

pantera1 [17]

Answer:

5 and 1/2

Step-by-step explanation: 2 goes into 11 5 times without passing it. That one that is left over would be the numerator and 2 as the demonator.

5 0

3 years ago

The vertex of the parabola below is at the point (2,4), and the point (3,6) is

lukranit [14]

Answer:

A. y= 2(x - 2)2 + 4

Step-by-step explanation:

vertex having an x value of 2 means the phrase in paren must be x - 2.

This eliminates B and D

vertex having a y value of 4 is of no help as the remaining two equations will result in 4 if the x term is 2

plugging in x = 3 makes y = 6 in equation A, but not in equation C where y = 10

3 0

3 years ago

Find the exact length of the curve. x = 1 + 6t2, y = 4 + 4t3, 0 ≤ t ≤ 3

vovangra [49]

$x=1+6t^2\implies\dfrac{\mathrm dx}{\mathrm dt}=12t$

$y=4+4t^3\implies\dfrac{\mathrm dy}{\mathrm dt}=12t^2$

The length of the curve $C$ is given by

$\displaystyle\int_C\mathrm ds=\int_0^3\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt$

$=\displaystyle\int_0^3\sqrt{144t^2+144t^4}\,\mathrm dt$

$=\displaystyle12\int_0^3t\sqrt{1+t^2}\,\mathrm dt$

$=\displaystyle6\int_0^3 2t\sqrt{1+t^2}\,\mathrm dt$

$=\displaystyle6\int_0^3\sqrt{1+t^2}\,\mathrm d(1+t^2)$

$=6\cdot\dfrac23(1+t^2)^{3/2}\bigg|_0^3$

$=4(10^{3/2}-1)$

$=40\sqrt{10}-4$

8 0

3 years ago

Decimal expansion for 2 over 3

katovenus [111]

. 66 the 6 keeps going on and on so you can just write. 66 with a line over the second 6.

3 0

3 years ago