To solve this problem, we make use of the Binomial
Probability equation which is mathematically expressed as:
P = [n! / r! (n – r)!] p^r * q^(n – r)
where,
n = the total number of gadgets = 4
r = number of samples = 1 and 2 (since not more than 2)
p = probability of success of getting a defective gadget
q = probability of failure = 1 – p
Calculating for p:
p = 5 / 15 = 0.33
So,
q = 1 – 0.33 = 0.67
Calculating for P when r = 1:
P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3
P (r = 1) = 0.3970
Calculating for P when r = 2:
P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2
P (r = 2) = 0.2933
Therefore the total probability of not getting more than
2 defective gadgets is:
P = 0.3970 + 0.2933
P = 0.6903
Hence there is a 0.6903 chance or 69.03% probability of
not getting more than 2 defective gadgets.
Answer:
a) 2x+4
b)x=8
Step-by-step explanation:
a) x+x+4 =2x +4
b) 2x+4= 20
2x = 16
x=8
Jay bought 8 packets of Chips
c) Jay: 8 x 60
=£4,80
Lauren : 12 × 60
= £7,2
This ordered pair is not a solution for the given equations. We can tell this by plugging in to each of them and seeing that it does not provide a true statement for both. It does work for the first, but is not an intersection due to it not working for each.
4x - 3y = 30
4(6) - 3(-2) = 30
24 + 6 = 30 (TRUE)
3x + 2y = 22
3(6) + 2(-2) = 22
18 - 4 = 22
16 =/= 22 (FALSE)
Y = 6, x = 5 y = 6, x = 5 y = 6, x = 5
