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ehidna [41]
3 years ago
5

The methods of the Character class that begin with ____ return a character that has been converted to the stated format.

Computers and Technology
1 answer:
Pavel [41]3 years ago
6 0

Answer:

most probably the answer is 'to'

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What file type starts at offset 0 with a hexidecimal value of ffd8?​?
kiruha [24]
The answer is jpeg.  It is <span>file type that starts at offset 0 with a hexidecimal value of ffd8?.  JPEG stands for </span>Joint Photographic Experts Group.  It is a popular image file format,  commonly used by digital cameras to store photos<span>. The format also supports different levels of compression, which makes it ideal for web graphics.</span>
5 0
3 years ago
What does amelia heart and the wright brothers have in common
expeople1 [14]

Answer:

they are stepbro and step sis and they fucx

Explanation:

7 0
2 years ago
I have no idea what I’m doing but this is for a class grade and also on Replit<br><br> Please Help!!
Tatiana [17]

Answer:

I've compiled some code below to help you out ;)

Explanation:

# Program make a simple calculator

# This function adds two numbers

def add(x, y):

   return x + y

# This function subtracts two numbers

def subtract(x, y):

   return x - y

# This function multiplies two numbers

def multiply(x, y):

   return x * y

# This function divides two numbers

def divide(x, y):

   return x / y

print("Select operation.")

print("1.Add")

print("2.Subtract")

print("3.Multiply")

print("4.Divide")

while True:

   # take input from the user

   choice = input("Enter choice(1/2/3/4): ")

   # check if choice is one of the four options

   if choice in ('1', '2', '3', '4'):

       num1 = float(input("Enter first number: "))

       num2 = float(input("Enter second number: "))

       if choice == '1':

           print(num1, "+", num2, "=", add(num1, num2))

       elif choice == '2':

           print(num1, "-", num2, "=", subtract(num1, num2))

       elif choice == '3':

           print(num1, "*", num2, "=", multiply(num1, num2))

       elif choice == '4':

           print(num1, "/", num2, "=", divide(num1, num2))

       

       # check if user wants another calculation

       # break the while loop if answer is no

       next_calculation = input("Let's do next calculation? (yes/no): ")

       if next_calculation == "no":

         break

   

   else:

       print("Invalid Input")

I got it from this link, https://www.programiz.com/python-programming/examples/calculator

3 0
2 years ago
One of the Visual Studio 2015 languages that can be used for rapid application development is C#. Another language that supports
Serga [27]

Answer:

Visual Basic is the appropriate answer for the following blank.

Explanation:

Visual Basic is a language based on real events of a third generation for the Module Object model coding model that was originally published and declared legacy in 2008.

  • In an easy to use graphical environment programmers can create a visual basic programming language for software interfaces and codes. VB is the collection of different components used with the help of the forms with specific characteristics and actions.
7 0
3 years ago
The following program is supposed to display a message indicating if the integer entered by the user is even or odd. What is wro
Lapatulllka [165]

Answer:

A. The function definition must appear before the function is called

Explanation:

Given

The above lines of code

Required

Determine the error in the program

In python, functions has be defined before they are called but in this case (of the given program), the function is called before it was defined and this will definitely result in an error;

<em>Hence, option A answers the question</em>

The correct sequence of the program is as follows:

<em>def evenOdd(n): </em>

<em>      if n % 2 == 0: </em>

<em>            return "even" </em>

<em>      return "odd" </em>

<em>num = int(input("Enter an integer: ")) </em>

<em>print("The integer is", evenOdd(num)) </em>

<em />

6 0
3 years ago
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