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7nadin3 [17]
3 years ago
11

Special numeric has three digits and holds a property that it is exactly equal to summation of cubes from each digit. For exampl

e, 370 is an element named special numeric. 370 = 3 3 + 7 3 + 0 3 . Write a C program to explore these special integer numbers from 100 to 999 and display all of them on screen. You can use for loop. Name your program f
Computers and Technology
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

The following code is written in C programming language:

#include <stdio.h>     //header file

 

int main()       //main method

{

   int n, t, digit1, digit2, digit3;      // set integer variables

    // print message

   printf("Print all Special integer numbers between 100 and 999:\n");

   n = 100;      //initialize value in variable "n"    

   while (n <= 999)      //set while loop

   {

       digit1 = n - ((n / 10) * 10);

       digit2 = (n / 10) - ((n / 100) * 10);

       digit3 = (n / 100) - ((n / 1000) * 10);

       t = (digit1 * digit1 * digit1) + (digit2 * digit2 * digit2) + (digit3 * digit3 * digit3);

       if (t == n)      //set if statement

       {

           printf("\n Special integer number is: %d", t);     //print an output

       }

       n++;

   }

}

Output:

Print all Special integer numbers between 100 and 999:

Special integer number is: 153

Special integer number is: 370

Special integer number is: 371

Special integer number is: 407

Explanation:

Here, we set the header file "stdio.h".

Then, we define integer type "main()" function.

Then, we set five integer type variable "n", "t", "digit1", "digit2", "digit3".

Then, we the print message by print() method and initialize a value to variable "n" to 100.

Then, we set the while loop which starts from 100 and stops at 999 and if the condition is true than code inside the loop is execute either loop is terminated.

Then, we set the if statement and pass the condition, if the condition is true the output would be print either if the condition is false the if statement is terminated.

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Select the correct answer.
juin [17]

Answer:

A. <Title> tag

Explanation:

Required

Tag that can be written in the <head> element

Of the given options, <title> is correct.

This is so because, it is compulsory to have the <title> tag and the only location where it can be placed is inside the <head> tag.

Its function is to display the title of a page

e.g.

<em><title> This is my first page </title></em>

4 0
3 years ago
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
Free up disk space by doing____?​
8090 [49]

Answer:

Deleting files and etc on your computer.

6 0
3 years ago
Read 2 more answers
Gwen's company is planning to accept credit cards over the Internet. Which one of the following governs this type of activity an
podryga [215]

Answer:

Payment Card Industry Data Standard(PCI DSS).

Explanation:

The online payment acceptance through credit cards is governed by the Payment Card Industry Data Standard (PCI DSS) and it also includes the provisions that shoulde be implemented by gwen's company before accepting any transaction through credit cards.

8 0
4 years ago
Write an algorithm to print the minimum and maximum of an integer array. Your need to pass the array as a parameter. Since we ca
sammy [17]

Answer:

See explaination

Explanation:

MinMax.java

import java.util.*;

public class MinMax

{

static void MinMax(int[] arr)

{

int Min=arr[0]; // initializinf min and max with 1st value of array

int Max=arr[0];

for(int i=0;i<arr.length;i++) // iterating loop only once

{

if(arr[i]>Max) // checking max value

{

Max=arr[i];

}

if(arr[i]<Min) // checking min value

{

Min=arr[i];

}

}

System.out.println("Min Number is "+Min); //printing min value

System.out.println("Max Number is "+Max); //printing max value

}

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.print("Enter N value: "); // taking n value

int n=sc.nextInt();

int[] arr=new int[n];

System.out.println("Enter N elements:"); // taking n elements into array

for(int i=0;i<n;i++)

{

arr[i]=sc.nextInt(); // each element into the array

}

MinMax(arr); // calling MinMax() method.

}

}

4 0
3 years ago
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