var theDate = new DateTime (DateTime.Today.Year, DateTime.Today.Month, DateTime.Today.Day, hours, minute, second);
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
Whats the question lmaoooooooooooooooooooooo
Answer:
Check the explanation
Explanation:
A) Whenever C is sending to D, what other communications are possible?
C’s packet will be seen by A, B and D, but not by E. Thus, D can send to E at the sametime..
B) Whenever B is sending to A, what other communications are likely?
Even though B’s packet will not be seen by D, other nodes, e.g., E, or C, can’t send to D since the packets from these nodes will interfere with the packets from B at A. Therefore, other communications is not likely at the same time.
C) Whenever B is sending to C, what other communications are possible?
B’s packet will be seen by E, A and C, by not by D. therefore, E can send to D at the same point.