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natima [27]
3 years ago
15

2x(3x2- 7x²+ 8) - 4(x4+9 - 7x3)

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

will this help any, i think its the answer

Step-by-step explanation:

-4 • (x4 - 5x3 - 4x + 9)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x3"   was replaced by   "x^3".  2 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (2x•(((3•(x2))-(7•(x2)))+8))-(4•(((x4)+9)-7x3))

Step  2  :

Polynomial Roots Calculator :

2.1    Find roots (zeroes) of :       F(x) = x4-7x3+9

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  9.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,3 ,9

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        17.00    

     -3       1        -3.00        279.00    

     -9       1        -9.00       11673.00    

     1       1        1.00        3.00    

     3       1        3.00        -99.00    

     9       1        9.00        1467.00    

Polynomial Roots Calculator found no rational roots

Equation at the end of step  2  :

 (2x•(((3•(x2))-(7•(x2)))+8))-4•(x4-7x3+9)

Step  3  :

Equation at the end of step  3  :

 (2x•(((3•(x2))-7x2)+8))-4•(x4-7x3+9)

Step  4  :

Equation at the end of step  4  :

 (2x•((3x2-7x2)+8))-4•(x4-7x3+9)

Step  5  :

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  8 - 4x2  =   -4 • (x2 - 2)

Trying to factor as a Difference of Squares :

6.2      Factoring:  x2 - 2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 2 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step  6  :

 -8x • (x2 - 2) -  4 • (x4 - 7x3 + 9)

Step  7  :

Step  8  :

Pulling out like terms :

8.1     Pull out like factors :

  -4x4 + 20x3 + 16x - 36  =

 -4 • (x4 - 5x3 - 4x + 9)

Checking for a perfect cube :

8.2    x4 - 5x3 - 4x + 9  is not a perfect cube

Trying to factor by pulling out :

8.3      Factoring:  x4 - 5x3 - 4x + 9

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -4x + 9

Group 2:  x4 - 5x3

Pull out from each group separately :

Group 1:   (-4x + 9) • (1) = (4x - 9) • (-1)

Group 2:   (x - 5) • (x3)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

8.4    Find roots (zeroes) of :       F(x) = x4 - 5x3 - 4x + 9

    See theory in step 2.1

In this case, the Leading Coefficient is  1  and the Trailing Constant is  9.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,3 ,9

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        19.00    

     -3       1        -3.00        237.00    

     -9       1        -9.00       10251.00    

     1       1        1.00        1.00    

     3       1        3.00        -57.00    

     9       1        9.00        2889.00    

Polynomial Roots Calculator found no rational roots

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Given:

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