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Harlamova29_29 [7]
3 years ago
9

What method can be used to write the equation of a line in slope-intercept form given two points?

Mathematics
2 answers:
stira [4]3 years ago
4 0

Answer:

The Answer is the first one, A                                            

Step-by-step explanation:

ioda3 years ago
4 0
<h2>Answer:</h2>

A∅ω∅

Step-by-step explanation:

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What is the amplitude of g(x) = 10 cos (6x - 1) – 4?
aev [14]

Answer:

im notm sure sorry

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the average rate of change of the amount of the element over the 10-minute experiment? *
Dima020 [189]

Answer:

-2.7  g/min

Step-by-step explanation:

Given: a graph

To find: the average rate of change of the amount of the element over the 10-minute experiment

Solution:

A rate of change of one quantity with respect to another quantity is known as rate of change. If y is the dependent variable and x is the independent variable then average rate of change = change in y /change in x.

From the graph,

change in x (time) = 10-0=10 minutes

change in y ( amount of the element) = 3.22-30=-26.78 g

So, average rate of change = \frac{-26.78}{10} =-2.7  g/min

7 0
3 years ago
Which Greek geometer founded a philosophical society that devoted itself to the study of mathematics?'
Luba_88 [7]

Answer:

Pythagoras

Step-by-step explanation:

Pythagoras

6 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
3t-8 I’m not sure pls help me
densk [106]

Answer: 3t-8

Step-by-step explanation:

<em>3t-8 is the answer because there are no like terms.</em>

<em />

6 0
3 years ago
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