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3 years ago

Drag each label to correct location on the image. Weather map

Physics

2 answers:

lilavasa [31]3 years ago

6 0

Answer:

Explanation:

yellow solid =severe thunderstorm

yellow dashed =severe thunderstorm

Red dashed = tornado watch

Red solid = tornado warning

Green = flash flood warning

hodyreva [135]3 years ago

5 0

Could you link or add the photo to this question?

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In science, Bob learns that the energy of a wave is directly proportional to the square of the waves amplitude. If the energy of

Naddika [18.5K]

Answer:

Probably none of the above. it's says directly proportional so there would be a proportionality constant.

4 0

4 years ago

The man fire a 50-g arrow that moves at an unknown speed. It hits and embeds in a 350-g block that slides on an air track. At th

Natasha_Volkova [10]

Answer:

a) vAix = 80 m/s

b) The assumptions and implications were:

Assume that friction between the block and the surface it rests on does not change the momentum of the system during the collision.

Assume that friction is negligible throughout the process and the system’s internal energy does not change.

Assume all the system’s kinetic energy is converted into elastic potential energy at the end of the process.

If any of the assumptions are invalid then the arrow must have been travelling initially, vAix > 80 m/s

Explanation:

Arrow embeds into block

Take in the first instance the system to be the arrow + block (isolated). Establish reference coordinate system with the +x axis running horizontally in the direction of the arrow’s motion. The initial state (i) is the arrow travelling with velocity vAix and the final state (f) is the arrow embedded in the block. Now, apply the component form of the Generalized Impulse Momentum Equation to this system:

pAi + pBi + JonA + JonB = pAf + pBf

pAix + pBix + Jx = pAfx + pBfx

mA*vAix + mB*vBix + 0 = (mA + mB)*vfx

0.05*vAix + 0 = (0.05 + 0.35)*vfx

vAix = 8*vfx (1)

Arrow embeds into block

Now consider the next phase of motion and take as the system the arrow + block + spring. The initial state (i) is the arrow and block travelling with velocity equivalent to the final velocity from equation 1 (final state velocity in first phase becomes initial velocity in next phase); vix’ = vfx and the final state (f) is the arrow + block brought to rest and the spring compressed an amount, Δx = 0.1 m. Now, apply the Generalized Work Energy Principle to the system

Ei + W = Ef

Ki + Usi + W = Kf + Usf

0.5*(mA + mB)*vix’² = 0.5*k*Δx²

(0.05 + 0.35)*vfx² = 4000*(0.1)²

vfx = √(40/0.4) = 10 m/s

Substituting above back into equation 1:

vAix = 8* 10 m/s = 80 m/s

Arrow embeds into block

The assumptions and implications were:

Assume that friction between the block and the surface it rests on does not change the momentum of the system during the collision.

Assume that friction is negligible throughout the process and the system’s internal energy does not change.

Assume all the system’s kinetic energy is converted into elastic potential energy at the end of the process.

If any of the assumptions are invalid then the arrow must have been travelling initially, vAix > 80 m/s

7 0

3 years ago

A beam of light strikes a sheet of glass at an angle of 57.0°. with the normal in air. You observe that red light makes an angle

Lena [83]

Answer:

a) Red: 1.34

Violet: 1.40

b) Red: $2.23\times10^8\frac{m}{s}$

Violet: $2.14\times10^8\frac{m}{s}$

Explanation:

a) We should use Snell's law to find the index of refraction:

$n_{1}sin\theta_{i}=n_{2}sin\theta_{t}$

with n1 the index of refraction of air, n2 the index of refraction of the glass, θi the angle of the incident ray respects the normal an θt the angle between the refracted ray an the normal. It's common to approximate n1=1

solving n2 for red light:

$\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}$

$n_2=\frac{sin57.0}{sin38.1}= 1.34$

solving n2 for violet light:

$\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}$

$n_2=\frac{sin57.0}{sin36.7}= 1.40$

b) Index of refraction on a medium is defined as the ratio between the velocity of electromagnetic waves on vacuum (velocity of light c) and the velocity in medium (v):

$n_2=\frac{c}{v}$

solving v for red:

$v=\frac{c}{n_2}=\frac{3\times10^8}{1.34}=2.23\times10^8\frac{m}{s}$

solving v for violet

$v=\frac{c}{n_2}=\frac{3\times10^8}{1.40}=2.14\times10^8\frac{m}{s}$

8 0

3 years ago

Electricity is transferred across step-up transformers to ...

Sindrei [870]

Answer:

Assuming that a transformer is 100 per cent efficient, the following equation can be used to calculate the power output from the transformer: A step-down transformer converts 11 500 V into 230 V ...

Explanation:

MARK AS BRAINLIEST AND HELP IN MY QUESTION IN PHYSICS

4 0

4 years ago

A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from re

valentinak56 [21]

Answer:

a) 17.33 V/m

b) 6308 m/s

Explanation:

We start by using equation of motion

s = ut + 1/2at², where

s = 1.2 cm = 0.012 m

u = 0 m/s

t = 3.8*10^-6 s, so that

0.012 = 0 * 3.8*10^-6 + 0.5 * a * (3.8*10^-6)²

0.012 = 0.5 * a * 1.444*10^-11

a = 0.012 / 7.22*10^-12

a = 1.66*10^9 m/s²

If we assume the electric field to be E, and we know that F =qE. Also, from Newton's law, we have F = ma. So that, ma = qE, and E = ma/q, where

E = electric field

m = mass of proton

a = acceleration

q = charge of proton

E = (1.67*10^-27 * 1.66*10^9) / 1.6*10^-19

E = 2.77*10^-18 / 1.6*10^-19

E = 17.33 V/m

Final speed of the proton can be gotten by using

v = u + at

v = 0 + 1.66*10^9 * 3.8*10^-6

v = 6308 m/s

5 0

3 years ago