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xenn [34]
3 years ago
7

An objects speed is the distance it travels____the amount of times it takes?

Physics
1 answer:
beks73 [17]3 years ago
8 0
Multiplied by; speed = distance x time
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In a coiled spring, the particles of the medium vibrate to and fro about their
Kitty [74]

Answer:

In a coiled spring, the particles of the medium vibrate to and fro about their mean positions at an angle of

A. 0° to the direction of propagation of wave

Explanation:

The waveform of a coiled spring is a longitudinal wave, which is made up of vibrations of the spring which are in the same direction as the direction of the wave's advancement

As the coiled spring experiences a compression force and is then released, it experiences a sequential movement of the wave of the compression that extends the length of the coiled spring which is then followed by a stretched section of the coiled spring in a repeatedly such that the direction of vibration of particles of the coiled is parallel to direction of motion of the wave

From which we have that the angle between the direction of vibration of the particles of the coiled spring and the direction of propagation of the wave is 0°.

8 0
2 years ago
3. During a tug-of-war, Team A pulls with a
Neko [114]

Answer:

8000 - 5000 =3000

Explanation:

8 0
2 years ago
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Ples help qustion in image
mash [69]

It is C) because that truck has more mass

8 0
3 years ago
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Can you help me please the question says
bearhunter [10]

Answer:

p= 4 m/v

Explanation:

v=l*w*h

v=(25)(2)(3)

v=150

p=600/150

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7 0
3 years ago
Beginning 145 miles directly south of the city of Hartville, a car travels due west. If the car is travelling at a speed of 42 m
ziro4ka [17]

Answer:

The rate of change of the distance is 14.89.

Explanation:

Given that,

Distance = 145 miles

Speed of car = 42 miles/hr

Distance covered by car = 55 miles

We need to calculate the the rate of change of the distance

According to figure,

Let OA is x, and AB is y.

Now, using Pythagorean theorem

x^2=y^2+145^2

On differentiating

2x\dfrac{dx}{dt}=2y\dfrac{dy}{dt}

\dfrac{dx}{dt}=\dfrac{y}{x}\dfrac{dy}{dt}

\dfrac{dx}{dt}=\dfrac{55\times42}{\sqrt{55^2+145^2}}

\dfrac{dx}{dt}=14.89\ miles/hr

Hence, The rate of change of the distance is 14.89.

8 0
3 years ago
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