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Alex_Xolod [135]

2 years ago

14

√85 between which two intergers

1 answer:

lilavasa [31]2 years ago

7 0

Answer:

I think that it is 9 and 10 because when you simply the number 85 it would be 9.21 which is round by 9

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

2 years ago

AABC is reflected across the x-axis. What is the new location of point B? A (-4, -2) C (4, -2) B (-4,2) D (4,2)

Molodets [167]

Answer:

D (4,2)

Step-by-step explanation:

you just change the y value to the opposite sign hehe

7 0

2 years ago

The diameter of a Frisbee is 12 inches. what's the area of the Frisbee?

xenn [34]

A= πr² = π × 6² = "113.1" is the area of the frisbee.

Please put me as brainliest.

7 0

3 years ago

Can u please help me please. Please

jonny [76]

The answer is
C = 4 ÷ 1/5

6 0

2 years ago

What is 100000000 plus 1234342343

Zielflug [23.3K]

Answer:

1,334,342,343 I think

6 0

2 years ago