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marusya05 [52]
3 years ago
9

The population of fish in a certain lake follows the logistic growth function f(t)=25000/1+8.25e^-0.076 where t is the time in y

ears. According to the growth model, what will the populations be after 20 years
Mathematics
2 answers:
krok68 [10]3 years ago
8 0

Answer:

The population will be approx 8915.

Step-by-step explanation:

The population of fish in a certain lake follows the logistic growth function -

f(t)=\frac{25000}{1+8.25e^{-0.076t} }

We have to find the population when t = 20

f(20)=\frac{25000}{1+8.25e^{-0.076(20)} }

=> \frac{25000}{1+8.25e^{-1.52} }

=> \frac{25000}{1+8.25(0.21871188)}

=> \frac{25000}{1+1.8044}

=> \frac{25000}{2.8044}

= 8914.56 or approx 8915.

The population will be approx 8915.

Vikentia [17]3 years ago
5 0

The population of fish in a certain lake follows the logistic growth function

f(x)= \frac{25000}{1+8.25e^{-0.076t}}

where t is the time in years. According to the growth model, what will the populations be after 20 years?

We are given with growth model f(x). In that , t represents the time in years.

To find out the population after 20 years, we plug in 20 for t and find out f(20)

f(x)= \frac{25000}{1+8.25e^{-0.076*20}}

=8914.65

The population after 20 years = 8914.65



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