Answer:
The profit will be maximum on x = 250.
Step-by-step explanation:
From the given information:
Revenue = 1500x - x²
Cost = 1500 + 1000x
As we know that
Profit = Revenue - Cost ; Let say it equation 1
Then after putting the values of revenue and cost in equation 1 we have:
Profit = (1500x - x²) - (1500 + 1000x)
Profit = 1500x - x² - 1500 - 1000x
Profit = -x² + 500x - 1500
We know that at the max or min the slope of the graph formed by the profit function will be zero, therefore we find the slope of profit function by taking the first derrivative w.r.t. x as under:
d(Profit)/dx = d/dx(-x² + 500x - 1500)
d(Profit)/dx = -2x + 500
By putting the above slope equal to zero we get:
d(Profit)/dx = -2x + 500 = 0
-2x + 500 = 0
-2x = -500
x = 250
Therefore it is concluded that the profit will be maximum when x will be equal to 250.
Is there more options because somethings missing
ΔACD and ΔASR are the same so we can write a ratio:
x/4 = 10/5
x/4 = 2
x/4 * 4 = 2 * 4
x = 8
Since AS is equal to x, they are both the same.
Therefore, the answer is [ x = 8, AS = 8 ]
Best of Luck!
Answer:
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200
Step-by-step explanation:
Given as :
Let The sum of money did Jeff have = $ x
The fraction of money did Jeff's wife get =
of $ x
The remaining money Jeff will have = $ x -
of $ x
I.e The remaining money Jeff will have =
=
A ) The remaining amount of money is divided equally among 4 children
So, The fraction of sum of money did each child receive = 
I.e The fraction of sum of money did each child receive =
B ) If each child will receive $ 600
∴,
= $ 600
Or, 3 x = $ 600 × 16
Or, 3 x = $ 9600
∴ x = 
I.e x = $ 3200
So, The sum of money did Jeff have $ 3200
Hence ,
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200 Answer
Answer:
maybe 223 degrees
Step-by-step explanation: