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hram777 [196]
3 years ago
13

Simplify. x0yz-3 1. xy/x^3 2. y/z^3 3. x/yz^3 4. 1/yz^3

Mathematics
2 answers:
german3 years ago
7 0

Answer:y/z^3

Step-by-step explanation:

eimsori [14]3 years ago
5 0
Answer is <span>2. y/z^3

-----------------

</span><span>x0yz-3 
= </span>yz-3  (because x*0 = 1)
= y/z^3
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Please help me with this one question, and I'll upvote the brainliest answer
ra1l [238]

Answer:   " x = 12 " .

________________________________________________

Step-by-step explanation:

________________________________________________

<u>Note</u>: If 2 (two) triangles are "similar" ;  then their corresponding sides are "proportional".

________________________________________________

Since one of the sides [the "hypotenuse"] of one the triangles given ; shows the measurement containing an expression with a value of "x" — specifically;  " 6x + 28 " ;  

    →  And since we want to solve for the value of "x" ;  we  use this "hypotenuse" of said particular triangle to set up a "proportion" with corresponding sides; so we can solve for "x" :

→  Set up proportions as a "ratio" ; or fraction:

       →  7:28::25:(6x + 28) ;  Solve for "x" ;

Let us write this in the form of a "fraction" :

      →  \frac{7}{28} = \frac{25}{(6x+28)} ;

________________________________________________

<u>Note</u>:  

        →  Rewrite:  " \frac{7}{28} " ; by simplifying to:

                                    " \frac{1}{4} " ;

________________________________________________

         →  Since:  " \frac{7}{28} " ;

              =  " (7÷7) / (28÷7) " ;

              =  " (1 /4) " ;

              =   " \frac{1}{4} " .

________________________________________________

Now, rewrite the "proportion" ; as follows:

________________________________________________

        \frac{1}{4} = \frac{25}{(6x+28)}  ;

________________________________________________

Now:   "Cross multiply" ;  that is:

______________________________________

→   Given:   " \frac{a}{b} = \frac{c}{d} " ;  

         and:  " b\neq0 " ;  " d\neq0 " ;

→  Then:   " a * d "  =  " b * c " .

________________________________________________

Likewise:   " 1(6x + 28)  =  (4) * (25) "   ;

______________________________________________

SImplify:    " 6x + 28 =  100 " ;  Solve for "x" ;

→ Subtract "28" from each side of the equation:

                  →   " 6x + 28 - 28 = 100 - 28 "  ;

    to get:   →   " 6x  =  72  "  ;

Now, divide each side of the equation by:  " 6 " ;

        to isolate "x" on one side of the equation; & to solve for "x" ; as follows:

   →   "  6x  =  72  "  ;

         →   6x / 6  =  72 / 6 ;

  to get:

         →   " x  = 12 "  ;

        →   which is the answer.

______________________________________________

Hope this helps!

  Best wishes in your academic pursuits

          — and within the "Brainly" community!

______________________________________________

5 0
2 years ago
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